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FinnZ [79.3K]
3 years ago
10

What are the zeros of the polynomial function y=2x^3-7x^2+2x+3?

Mathematics
1 answer:
zlopas [31]3 years ago
7 0

y = 2 {x}^{3}  - 7 {x}^{2}  + 2x + 3

By inspection 1 is a root of y ,
Hence , (x-1) is a factor of y ,

\dfrac{2 {x}^{3} - 7 {x}^{2}  + 2x + 3 }{x - 1}  = 2 {x}^{2}  - 5x - 3 \\  \\ 2 {x}^{2}  - 5x - 3 = (2x + 1)(x - 3)

Hence , the 2 other roots are -1/2 and 3 , and the above graphs confirms the same.

Hope it helps you :)

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Step-by-step explanation:

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Likurg_2 [28]

Answer:

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Step-by-step explanation:

To find : Calculate the Laplace transforms of the following from the definition ?

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We know that,

Laplace transforms of t^n is given by,

L(t^n)=\frac{n!}{s^{n+1}}

1) y=t^2

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