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3 years ago

5

I need help with this question

1 answer:

MatroZZZ [7]3 years ago

5 0

The sequence of keystrokes directs the calculator to compute

$\dfrac{5\cdot 10^{-9}}{2\cdot 10^4}=\dfrac{5}{2}\cdot 10^{(-9-4)}=2.5\cdot 10^{-13}$

The display will read ...

... A) 2.5E-13

_____

You can enter these keystrokes on your calculator and get the answer immediately.

___

Actually, it is very likely Samuel's calculator displayed 2E4, since the key for "=" has not been pressed.

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Find the measure of angle ABC

victus00 [196]

First we need to find x so 6x+8x+6x= 180
20x=180 and x= 9

So A= 6*9= 54
B= 8*9= 72
C= 6*9= 54

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2 years ago

5. Find the triangle similar to AABC at the right.

Alex Ar [27]

Answer:

the answer is b

Step-by-step explanation:

7 0

2 years ago

All together, 3 people have 120 coins. mark has 3 times as many as joel, and joel has 1/2 as many as sandra. how many coins does

oksano4ka [1.4K]

Joel = j, Mark = m, Sandra = s
j + m + s = 120
m = 3j
j = 1/2 s --> s = 2j
plug in (substitute) each letter to make it in terms of only j: j + m + s = 120
j + 3j + 2j = 120
6j = 120
6j/6 = 120/6
j = 20
now plug in for the j & s equation:
s = 2j = 2(20) = 40
Therefore Sandra has 40 coins!

7 0

3 years ago

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)

vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

$x^{\frac{2}{3}}+y^{\frac{2}{3}}=4$

We have to find the equation of tangent line to the given curve at point $(-3\sqrt3,1)$

By using implicit differentiation, differentiate w.r.t x

$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

$\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}$

$\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}$

$\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}$

Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

$\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}$

Slope of tangent=m= $\frac{1}{\sqrt3}$

Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

$y-1=\frac{x}{\sqrt3}+3$

$y=\frac{x}{\sqrt3}+3+1$

$y=\frac{x}{\sqrt3}+4$

This is required equation of tangent line to the given curve at given point.

8 0

3 years ago

Find the value of x round to the nearest tenth

wolverine [178]

Answer:

sin 76 = 13/x

x=13/sin 76

x=13.3979771816

x=13.4

6 0

2 years ago