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solong [7]
2 years ago
12

Find the area of 21m,11m,16m,14m,5m,35m,

Mathematics
1 answer:
Butoxors [25]2 years ago
7 0

Answer:

pls I don't understand the question can u explain

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8 0
2 years ago
Find the value of y.<br> 24<br> 18<br> у<br> Answer:
stiv31 [10]

Answer:

12

Step-by-step explanation:

It has been going down by 6 because 24-6=18 and 18-6=12.

6 0
3 years ago
(02.01)Which translation will change figure ABC to figure A'B'C'?
liq [111]

Answer:

4 units right and 3 units up.

Step-by-step explanation:

6 0
3 years ago
What is the relationship between A: Vertical angles <br> B: Complementary angles <br> C: Supplementary angles <br> D: None of th
NNADVOKAT [17]

Answer:

B. Complementary Angles

Step-by-step explanation:

They both make up 90 degree angle.

3 0
4 years ago
6. Find an exact value. (1 point)
vladimir2022 [97]
<span>6 Find an exact value. 
sin 75°
</span>sin(A+B)=sin(A)cos(B)+cos(A)sin<span>(B)
</span>sin(45)=cos(45)=(2^0.5)/2    sin(30)=0.5      cos(30)=(3^0.5)/2
sin(45+30)=sin(45)cos(30)+cos(45)sin(30)=(6^0.5+2^0.5)/4
the answer is the letter d) quantity square root of six plus square root of two divided by four.

<span>7. Find an exact value. 
sine of negative eleven pi divided by twelve.

</span>sin(-11pi/12) = -sin(11pi/12) = -sin(pi - pi/12) = -sin(pi/12) = -sin( (pi/6) / 2)

= - sqrt( (1-cos(pi/6) ) / 2) = -sqrt( (1-√3/2) / 2 ) = -(√3-1) / 2√2=(√2-√6)/4
the answer is the letter c) quantity square root of two minus square root of six divided by four.

<span>8. Write the expression as the sine, cosine, or tangent of an angle. 
sin 9x cos x - cos 9x sin x
</span>

sin(A−B)=sinAcosB−cosAsinB

sin(9x−x)= sin9xcosx−cos9xsinx= sin(8x)

the answer is the letter c) sin 8x

<span>9. Write the expression as the sine, cosine, or tangent of an angle. 
cos 112° cos 45° + sin 112° sin 45°

</span>

cos(A−B)=cosAcosB<span>+sinA</span>sinB

cos(112−45)=cos112cos45<span>+sin112</span>sin45=cos(67)

the answer is the letter d) cos 67°

10. Rewrite with only sin x and cos x.

sin 2x - cos 2x

 

sin2x = 2sinxcosx<span>
cos2x = (cosx)^2 - (sinx)^2 = 2(cosx)^2 -1 = 1- 2(sinx)^2</span>

sin2x- cos2x=2sinxcosx-(1- 2(sinx)^2=2sinxcosx-1+2(sinx)^2

sin2x- cos2x=2sinxcosx-1+2(sinx)^2

<span>the answer is the letter <span>b) 2 sin x cos2x - 1 + 2 sin2x</span></span>
4 0
3 years ago
Read 2 more answers
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