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2 years ago

Find the area of 21m,11m,16m,14m,5m,35m,

Mathematics

1 answer:

Butoxors [25]2 years ago

7 0

Answer:

pls I don't understand the question can u explain

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Zoe plants a sunflower seed and

Len [333]

Answer:

44.52 inches

Step-by-step explanation:

If it grows 3.71 inches per month for 12 months, you need to multiply 3.71 by 12, which gives you 44.52.

7 0

3 years ago

Please help its due soon! :(

mariarad [96]

Answer:

So, the correct answer is that as x gets bigger, f(x) moves towards positive infinity.

7 0

1 year ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

3 years ago

Help me I don’t understand

Fantom [35]

Answer:

<1= 32*

<2= 32*

<3= 40*

Step-by-step explanation:

a triangle also adds up to 180*

m <1 = 90+58=148 then 180-148=32*

<1 and <2 are equal so <2 also =32*

m <3= 108+32=140 then 180-140=40

6 0

2 years ago

Help plz it’s my final grade besties

Furkat [3]

blank table values:

1, 2, 4, 8, 16, 32, 64

(2,4) and (6,64)

y = 1 * $2^{x}$

$2^{20}$ = 1048576

5 0

3 years ago