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solong [7]
2 years ago
12

Find the area of 21m,11m,16m,14m,5m,35m,

Mathematics
1 answer:
Butoxors [25]2 years ago
7 0

Answer:

pls I don't understand the question can u explain

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Zoe plants a sunflower seed and
Len [333]

Answer:

44.52 inches

Step-by-step explanation:

If it grows 3.71 inches per month for 12 months, you need to multiply 3.71 by 12, which gives you 44.52.

7 0
3 years ago
Please help its due soon! :(
mariarad [96]

Answer:

So, the correct answer is that as x gets bigger, f(x) moves towards positive infinity.

7 0
1 year ago
in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)
Nimfa-mama [501]

Answer:

The component of \vec u orthogonal to \vec a is \vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right).

Step-by-step explanation:

Let \vec u and \vec a, from Linear Algebra we get that component of \vec u parallel to \vec a by using this formula:

\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a (Eq. 1)

Where \|\vec a\| is the norm of \vec a, which is equal to \|\vec a\| = \sqrt{\vec a\bullet \vec a}. (Eq. 2)

If we know that \vec u =(2,1,1,2) and \vec a=(4,-4,2,-2), then we get that vector component of \vec u parallel to \vec a is:

\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)

\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)

\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)

Lastly, we find the vector component of \vec u orthogonal to \vec a by applying this vector sum identity:

\vec  u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a} (Eq. 3)

If we get that \vec u =(2,1,1,2) and \vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right), the vector component of \vec u is:

\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10}    \right)

\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)

The component of \vec u orthogonal to \vec a is \vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right).

4 0
3 years ago
Help me I don’t understand
Fantom [35]

Answer:

<1= 32*

<2= 32*

<3= 40*

Step-by-step explanation:

a triangle also adds up to 180*

m <1 = 90+58=148 then 180-148=32*

<1 and <2 are equal so <2 also =32*

m <3= 108+32=140 then 180-140=40

6 0
2 years ago
Help plz it’s my final grade besties
Furkat [3]

a)

blank table values:

1, 2, 4, 8, 16, 32, 64

(2,4) and (6,64)

b)

y = 1 * 2^{x}

2^{20} = 1048576

5 0
2 years ago
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