Answer:
The volume of a right circular cylinder with a base diameter of 17.5 ft and a height of 24.5 ft is:
5889.95 ft³
Step-by-step explanation:
We are given a base diameter of a right circular cylinder as :
d = 17.5 ft.
hence radius of cylinder i.e. r =d/2 = 8.75 ft.
height of the cylinder = 24.5 ft.
now we know that volume of cylinder i.e. V is given by :
V = πr²h
putting the value of r and h in the given formula to obtain the volume
V = 3.14×(8.75)²×24.5
= 5889.95 ft³
hence, the volume of a right circular cylinder with a base diameter of 17.5 ft and a height of 24.5 ft is:
5889.95 ft³
Answer:
just relax take ur time and breath or just look it up
Step-by-step explanation:
inhale
exhale
you got this my friand
Answer:
Ok, first in our series we can see two numbers in the Sigma, one bellow 0, and other above, 4.
This means that the value of k will go from 0 to 4, then all the numbers in the sum are:
(-1/2)^0 + (-1/2)^1 + (-1/2)^2 + (-1/2)^3 + (-1/2)^4
So we have 5 terms in our series.
b) to see the sign in each term, we must solve the powers, remember that:
(-1)^n is -1 if n is odd, and is equal to 1 if n is even, so we have:
(-1/2)^0 + (-1/2)^1 + (-1/2)^2 + (-1/2)^3 + (-1/2)^4
= 1 -1/2 + 1/4 - 1/8 + 1/16.
So the sign in each term of the series alternates.
Answer:
20/5 = x /4 x = 80/5 = 16
x - 10 / 39 = 5/15 = 1/3
3x - 30 = 39
3x = 69
x = 23
(2x + 10 ) * 4 = 10 *(x + 3)
8x + 40 = 10x + 30
2x = 10
x = 4.
AE = 2(5) + 10 = 20, hope this helped.
