<span>Acceleration of a passenger is centripetal acceleration, since the Ferris wheel is assumed at uniform speed:
a = omega^2*r
omega and r in terms of given data:
omega = 2*Pi/T
r = d/2
Thus:
a = 2*Pi^2*d/T^2
What forces cause this acceleration for the passenger, at either top or bottom?
At top (acceleration is downward):
Weight (m*g): downward
Normal force (Ntop): upward
Thus Newton's 2nd law reads:
m*g - Ntop = m*a
At top (acceleration is upward):
Weight (m*g): downward
Normal force (Nbottom): upward
Thus Newton's 2nd law reads:
Nbottom - m*g = m*a
Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame:
Ntop = m*(g - a)
Nbottom = m*(g + a)
Substitute a:
Ntop = m*(g - 2*Pi^2*d/T^2)
Nbottom = m*(g + 2*Pi^2*d/T^2)
We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground):
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g)
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g)
Simplify:
Ntop/(m*g) = 1 - 2*Pi^2*d/(g*T^2)
Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2)
Data:
d:=22 m; T:=12.5 sec; g:=9.8 N/kg;
Results:
Ntop/(m*g) = 71.64%...she feels "light"
Nbottom/(m*g) = 128.4%...she feels "heavy"</span>
Answer:
AC = 16 in.
Step-by-step explanation:
AD = CD = 10 in.
BD = 6 in.
AC = 2(AB) = ?
Apply pythagorean theorem to find AB
AB² = AD² - BD²
Substitute
AB² = 10² - 6²
AB² = 64
AB = √64
AB = 8
Therefore:
AC = 2(AB) = 2(8)
AC = 16 in.
Answer:
The answer is the second option
Step-by-step explanation:
V=Bh
We need to get rid of expression parentheses.
If there is a negative sign in front of it,
each term within the expression changes sign.
Otherwise, the expression remains unchanged.
Numerical 'like' terms will be added. There is only one group of like terms
the answer is: ab-4a-5
<span />
Lamar used 80% of his data, so he used a greater percentage.
