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Len [333]
3 years ago
15

Recall that the standard basis of ℝ3 is {E1, E2, E3}. If T:ℝ3→ℝ2 is a transformation and the action of T on the vectors Ei is as

given, find a formula for T(X), where X is any vector in ℝ3.
T(E1)= 2 T(E2)= \begin{bmatrix} 0 \\ 5 \end{bmatrix} T(E3) = \begin{bmatrix} 4 \\ 0 \end{bmatrix}

T\begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} ? \\ ? \\ ? \end{bmatrix}

Mathematics
1 answer:
omeli [17]3 years ago
4 0

Answer:

Your question is not clear.  But it seems like the answer could be like the one at the images.

Step-by-step explanation:

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grandma has 30 pages in her photo album each page has two rows with five pictures and each row how many pictures are in Grandma'
Natalka [10]
2*5*30=300 pictures
..........................
7 0
3 years ago
The first barn contained 3 times more hay than the second one. After 20 tons of hay were removed from the first barn and 20 tons
pentagon [3]

Answer:

Amount of hay in first barn = 90 tons

Amount of hay in second barn song = 30 tons                

Step-by-step explanation:

Let the amount of hay in second barn be x, then hay in first barn will be 3x.

20 tons of hay was removed from first barn and ws added to second barn.

Now, the amount of hay in first barn = 3x -20

Amount of hay in second barn = x+20

The equation now formed is:

x+20 = \frac{5}{7}(3x-20)

7x+14 = 15x -100

-8x = -240

8x = 240

x = 30

3x = 90

Amount of hay in first barn = 90 tons

Amount of hay in second barn song = 30 tons          



6 0
4 years ago
Kevin and Randy Muise have a jar containing 46 coins, all of which are either quarters or nickels. The total value of the coins
Zepler [3.9K]

Answers:

24 quarters

22 nickels

==========================================================

Work Shown:

q = number of quarters

n = number of nickels

q+n = 46 coins total which solves to n = 46-q

25q = value of all the quarters in cents

5n = value of all the nickels in cents

25q+5n = value (cents) of all the coins of both types

25q+5n = 710 cents total = $7.10

-------------

Apply substitution.

25q+5n = 710

25q+5(46-q) = 710

25q+230-5q = 710

20q+230 = 710

20q = 710-230

20q = 480

q = 480/20

q = 24

They have 24 quarters

This yields 25*q = 25*24 = 600 cents = $6.00 so far.

Use that value of q to find n

n = 46-q

n = 46-24

n = 22

They also have 22 nickels.

They have an additional 5n = 5*22 = 110 cents = $1.10

In total, they have 6.00+1.10 = 7.10 dollars which confirms we have the correct coin counts. Also, q+n = 24+22 = 46.

8 0
3 years ago
State what method you would use to solve the equation. Justify your answer. You do not need to solve the equation.
aleksandrvk [35]

Answer:

By factoring

Step-by-step explanation:

4x^2+25=20x then:

4x^2-20x+25=0

factoring:

(2x-5)(2x-5)=0

2x=5, x=2.5

5 0
3 years ago
What ordered pair is the solution to -7x+3y=2
goldenfox [79]

Answer:

Step-by-step explanation:

3y=7x+2

y=\frac{7x+2}{3}\\x=1,y=3\\

one pair is (1,3)

go on adding  3 in x=1,you get corresponding value of y.

x=4,y=10,(4,10)

and so on .

7 0
4 years ago
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