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katrin2010 [14]
2 years ago
5

Hours spent volunteering

Mathematics
1 answer:
iris [78.8K]2 years ago
7 0

Answer:

week mo naman salamat sa points

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A spring stretches out by 8cm when a 0.2 kg weight is placed on it. How much does the spring stretch by when a 0.5 kg weight is
Ierofanga [76]

m₁ = mass hanged initially = 0.2 kg

x₁ = initial stretch in the spring = 8 cm = 0.08 m

k = spring constant of the spring

the weight of the mass hanged is balanced by the spring force by the spring hence

Spring force = weight of mass hanged

k x₁ = m₁ g

k (0.08) = (0.2) (9.8)

k = 24.5 N/m


m₂ = mass hanged later = 0.5 kg

x₂ = final stretch in the spring = ?

k = spring constant of the spring = 24.5 N/m

the weight of the mass hanged is balanced by the spring force by the spring hence

Spring force = weight of mass hanged

k x₂ = m₂ g

(24.5) x₂  = (0.5) (9.8)

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3 years ago
This is Mrs. Galicia’s solution for the equation. Is Mrs. Galicia’s solution correct? Explain in complete sentences also, what a
horrorfan [7]

<u>Given</u>:

Given that Mrs. Galicia’s solution for the equation.

We need to determine whether Mrs. Galicia’s solution is correct or not.

Also, we need to determine the correct solutions.

<u>Mrs. Galicia’s solution:</u>

Step 4: (x-4)^2=25

Step 5: x-4=25

After step 4, Mrs. Galicia’s did not take square root on both sides to determine the value of x.

Thus, Mrs. Galicia’s made in mistake in step 5, by solving the equation without taking square root on both sides.

Hence, Mrs. Galicia’s solution is wrong.

<u>Correct solutions:</u>

The equation is x^{2} -8x-9=0

Solving, we get;

x^2-8x=9

Completing the square, we have;

x^2-8x+16=9+16

      (x-4)^2=25

Taking square root on both sides, we get;

x-4=\pm 5

Thus, the values of x are given by

x-4=5 and x-4=-5

     x=9 and       x=-1

Thus, the correct solutions are x = 9 and x = -1

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