Answer:
The equation of the graphed line written in standard form is:x-y=0
Step-by-step explanation:
we know that for graphing lines the equation of a line must be in standard form.
the standard form of a line is given by 
where a,b,c are some real numbers.
hence, in the given question for graphing our line we must use the equation 
because on comparing it to the general equation of the line we have here a=1, b=-1 and c=0.
therefore the standard form is:
Answer:
- The value of
- The value of
Step-by-step explanation:
Let
and
As 
is exactly divisible, so, the remainder is 0.
∴ 
As the R.H.S becomes 0 when 
and 
.
And
by substituting
![25 + 20( \frac{\sqrt{5}}{\sqrt{2}} ) + a( \frac{\sqrt{5}}{\sqrt{2}}) +b =0...[A]](https://tex.z-dn.net/?f=25%20%2B%2020%28%20%5Cfrac%7B%5Csqrt%7B5%7D%7D%7B%5Csqrt%7B2%7D%7D%20%29%20%2B%20a%28%20%5Cfrac%7B%5Csqrt%7B5%7D%7D%7B%5Csqrt%7B2%7D%7D%29%20%2Bb%20%3D0...%5BA%5D)
by substituting
![25 - 20( \frac{\sqrt{5}}{\sqrt{2}} ) - a( \frac{\sqrt{5}}{\sqrt{2}}) +b =0.....[B]](https://tex.z-dn.net/?f=25%20-%2020%28%20%5Cfrac%7B%5Csqrt%7B5%7D%7D%7B%5Csqrt%7B2%7D%7D%20%29%20-%20a%28%20%5Cfrac%7B%5Csqrt%7B5%7D%7D%7B%5Csqrt%7B2%7D%7D%29%20%2Bb%20%3D0.....%5BB%5D)
Adding Equation [A] and equation [B]
Subtracting Equation [A] and equation [B]
Therefore,
- The value of
- The value of
<em>Keywords:</em><em> equation, solution</em>
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Answer C explanation: Alternate interior angles are always congruent
make it exuavalent and answer. what i taught is the answer is in the q. itself
