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natulia [17]
3 years ago
5

What is the perimeter in square units of the rectangle shown on the coordinate grid?

Mathematics
2 answers:
Likurg_2 [28]3 years ago
5 0

Answer:

A

Step-by-step explanation:

The opposite sides of a rectangle are congruent.

Calculate the lengths of 2 of the sides using the distance formula and multiply by 2

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 2, 10) and (x₂, y₂ ) = (2, 7)

d = \sqrt{(2+2)^2+(7-10)^2}

   = \sqrt{4^2+(-3)^2}

   = \sqrt{16+9} = \sqrt{25} = 5

Repeat

with (x₁, y₁ ) = (- 8, 2) and (x₂, y₂ ) = (- 2, 10)

d = \sqrt{(-2+8)^2+(10-2)^2}

  = \sqrt{6^2+8^2}

   = \sqrt{36+64} = \sqrt{100} = 10

Hence

Perimeter = (2 × 5) + (2 × 10) = 10 + 20 = 30 units → A

Rashid [163]3 years ago
4 0

In order to find the Perimeter of the Rectangle, First we need to find the Length and Width of the Rectangle.

Distance between two points (x₁ , y₁) and (x₂ , y₂) is given by :

\bigstar\;\; \mathsf{Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}

There are two lengths in a rectangle. Let us find any one length of the rectangle.

I'm considering the length with co-ordinates (-8 , 2) and (-2 , 10)

Here :  x₁ = -8 and x₂ = -2 and y₁ = 2 and y₂ = 10

Substituting the values in the distance formula, We get :

\mathsf{\implies Length = \sqrt{[-2 - (-8)]^2 + [10 - 2]^2}}

\mathsf{\implies Length = \sqrt{[-2 + 8]^2 + [8]^2}}

\mathsf{\implies Length = \sqrt{[6]^2 + [8]^2}}

\mathsf{\implies Length = \sqrt{36 + 64}}

\mathsf{\implies Length = \sqrt{100}}

\mathsf{\implies Length = 10}

There are two widths in a rectangle. Let us find any one width of the rectangle.

I'm considering the width with co-ordinates (-2 , 10) and (2 , 7)

Here :  x₁ = -2 and x₂ = 2 and y₁ = 10 and y₂ = 7

Substituting the values in the distance formula, We get :

\mathsf{\implies Width = \sqrt{[2 - (-2)]^2 + [7 - 10]^2}}

\mathsf{\implies Width = \sqrt{[2 + 2]^2 + [-3]^2}}

\mathsf{\implies Width = \sqrt{[4]^2 + [-3]^2}}

\mathsf{\implies Width = \sqrt{16 + 9}}

\mathsf{\implies Width = \sqrt{25}}

\mathsf{\implies Width = 5}

Perimeter of a Rectangle is given by : 2[Length + Width]

:\implies  Perimeter of the given rectangle = 2[10 + 5]

:\implies  Perimeter of the given rectangle = 2[15]

:\implies  Perimeter of the given rectangle = 30

<u>Answer</u> : Perimeter of the given rectangle is 30 square units

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