The value of the bike after a year becomes only 80% of the value a year ago. In this given, the initial amount $500 should be multiplied by 80% 5 times. The answer would be $163.84. Thus, after 5 years the dirt bike would only be $163.84.
Step-by-step explanation:
We have:
x - y = 43 , xy = 15
To find, the value of x^2+y^2x
2
+y
2
= ?
∴ x - y = 43
Squaring both sides, we get
(x - y)^2(x−y)
2
= 43^243
2
⇒ x^2+y^2x
2
+y
2
- 2xy = 1849
Using the algebraic identity,
(a - b)^2(a−b)
2
= a^2+b^2a
2
+b
2
- 2ab
⇒ x^2+y^2x
2
+y
2
= 1849 + 2xy
Put xy = 15, we get
x^2+y^2x
2
+y
2
= 1849 + 2(15)
⇒ x^2+y^2x
2
+y
2
= 1849 + 30
⇒ x^2+y^2x
2
+y
2
= 1879
∴ x^2+y^2x
2
+y
2
= 1879
I will send hint follow this hint then slove it .
thankyou
Craig has every 13th night and Edie has every 5th night off.
You have to find LCM - the Least Common Multiple that is the smallest ("least") number that both 13 and 5 will divide into.
Since numbers 13 and 5 are both prime, then LCM(13,5)=13·5=65.
This means, they will have the same every 65th night off.
7(200 + 50 + 6) = (7 x 200) + (7 x 50) + (7 x 6) = 1,400 + 350 + 42 = 1,792
