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marysya [2.9K]
2 years ago
15

If f(x) =x^2 -2 and g(x) = 4f(x)-1 then what is the value of g(-3)?

Mathematics
2 answers:
In-s [12.5K]2 years ago
8 0

Answer:

I believe that g(-3) = -9. I could be wrong though.

Tell me if I'm correct and have a good day!!!


lakkis [162]2 years ago
3 0

g(x) = 4f(x)-1

g(x) = 4(x^2-2) -1

g(3) = 4(3^2-2) -1

      = 4(9-2) -1

      =4*7 -1

 = 28-1

=27

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4 0
3 years ago
Explain how you can find whether 5/6 or 5/8 is greater
ratelena [41]
Because The Smaller The Denominators The Bigger The Fraction Pieces So The Denominators With 6 And 8 The Six Is Smaller So The 5/6 Will be Greater Than 5/8 . 

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4 0
3 years ago
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The sea ice area around the North Pole fluctuates between about 6 million square kilometers in September to 14 million square ki
Aleksandr [31]

Answer:

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Given the data in the question;

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Now, we use a cosine curve to model this scenario

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Now, the horizontal stretch factor will be;

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Hence;

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Now we find when there will be less than 9 million square meters of sea ice;

S(t) = 9

so we have

9 = 4cos( π/6 × (t-2) ) + 10

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so we have;

cos⁻¹( -1/4 ) = π/6 × (t₁-2)  -------- let this be equation 2

2π - cos⁻¹( -1/4 ) = π/6 × (t₂-2)  -------- let this be equation 3

so we solve equation 2 and 3

we have'

t₁ - t₂ = 6/π × ( 2π - cos⁻¹( -1/4 ) - cos⁻¹( -1/4 ) )

t₁ - t₂ = 6/π × ( 2π - 2cos⁻¹( -1/4 )  

t₁ - t₂ = 6/π × ( π - cos⁻¹( -1/4 )  

t₁ - t₂ = 6/π × ( π - 104.4775 )

t₁ - t₂ = 6/π × ( π - 104.4775 )  

t₁ - t₂ = 5.035

therefore, there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

6 0
2 years ago
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Answer:

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3 0
3 years ago
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