$3x^3-2y^3-6x^2y^2+xy=\\\\=3\cdot(\frac{2}{3})^3-2\cdot(\frac{1}{2})^3-6\cdot(\frac{2}{3})^2\cdot(\frac{1}{2})^2+\frac{2}{3}\cdot\frac{1}{2}=\\\\=3\cdot\frac{8}{27}-2\cdot\frac{1}{8}-6\cdot\frac{4}{9}\cdot\frac{1}{4}+\frac{1}{3}=\\\\=\frac{8}{9}-\frac{1}{4}-\frac{2}{3}+\frac{1}{3}=\frac{8}{9}-\frac{1}{4}-\frac{1}{3}=\frac{32}{36}-\frac{9}{36}-\frac{12}{36}=\boxed{\frac{11}{36}}$

5 0

2 years ago

Round 10.95 to the nearest tenth

Serhud [2]

Hi there! To round 10.95 to the nearest tenth, we find the number in the tenth place, which is 9 and look one place to the right. Round up if the number is greater than 5 or equal to 5 and round down if its less than 5.

The answer is 11.0 or just 11.

<em>Ed: Explanation below.</em>

<em />

11.00

10.99

10.98

10.97

10.96

10.95 Look at the 9. Then look to the right. Do I round up or down?

10.94

10.93

10.92

10.91

10.90

If the number is greater or equal to 5, you round up. If the number is smaller than 5, you round down. 9 is greater than 5, so we round up.

Therefore, the answer is 11.

5 0

3 years ago

Find the perimeter of a square pool with a length of 14 feet

slamgirl [31]

56 feet.....................

5 0

3 years ago

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