probability that a dessert sold at a certain cafe contains chocolate is 86%.
The probability that a dessert containing chocolate also contains nuts is 30%.
Find the probability that a dessert chosen at random contains nuts given that it contains chocolate
P(nuts given chocolate) = .30/.86 = .349 or 34
Answer:
a) 25446.90 ft²
b) 101787.60 ft²
c) 407150.41 ft²
d) 2025πt²
Step-by-step explanation:
Data provided in the question:
Rate of spread radially = 45 feet per day
a) Radius of spread after 2 days
= 45 × 2
= 90 feet
Therefore,
Area affected = πr²
= π(90)²
= 25446.90 ft²
b) Radius of spread after 2 days
= 45 × 4
= 180 feet
Therefore,
Area affected = πr²
= π(180)²
= 101787.60 ft²
c) Radius of spread after 2 days
= 45 × 8
= 360 feet
Therefore,
Area affected = πr²
= π(360)²
= 407150.41 ft²
a) Radius of spread after t days
= 45 × t ft
Therefore,
Area affected = πr²
= π(45t)²
= 2025πt²
A = (-2,3)
B = (4,6)
Let d = distance betweeb A and B
Y² -9=0
a=1, b=0, c=-9
0² -4*1*(-9)
y=36
