If angle AEC is 90° and angle AEB bisects it and is 45° that right there proves that angle AEB bisects angle AEC
Answer:
3
Step-by-step explanation:
3/4 divided by 1/4 equals 3
The cosine of 30° is √3 / 2.
Since cosine is Adjacent over Hypotenuse, Hypotenuse = (2 / √3) * 9 = 18 / √3.
The cosine of 45° is √2 / 2.
Therefore, X = (2 / √2) * (18 / √3) = 36 / √6 = 18 / √1.5 = C
Answer:
in confused on what to help u with
Step-by-step explanation:
I believe the answer should be 77
