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My name is Ann [436]
4 years ago
12

How do you solve system of eqautions using substitution

Mathematics
1 answer:
Licemer1 [7]4 years ago
8 0
Well basically you are plugging in variables. Lets use a random but simple system of equations.
y = 2x - 3
6x + 8y = 20
Now you need to plug in the top equation, which equals y, into the bottom equation.
6x + 8(2x - 3) = 20
6x + 16x - 24 = 20
Combine like terms.
22x - 24 = 20
Add 24 to both sides.
22x = 44
Divide.
x = 2
Now plug in 2 in any of the original equations.
y = 2x - 3
y = 2(2) - 3
y = 4 - 3
y = 1
So your solution is (2,1). And thats how you use substitution.
I hope this helps love! :)
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3 years ago
Sara has 24 sweets
Tresset [83]
<h2>Hello!</h2>

The answer is:

The expression for the number of sweets that Sara and Tim have now, are:

Sara=(17-x)Sweets\\\\Tim=\frac{(24+x)Sweets}{2}

<h2>Why?</h2>

To write the expressions for the number of sweets that Sara and Tim have now, we need to follow the next steps:

Sara starts with 24 sweets and Tim starts with 24 sweets

Sara=24 Sweets\\Tim=24 Sweets

Then, Sara gives Tim x Sweets

Sara=(24-x)Sweets\\Tim=(24+x)Sweets

Then. Sara eats 7 of her Sweets

Sara=(24-x-7) Sweets\\Sara=(17-x )Sweets\\Tim=(24+x) Sweets

Then, Tim eats half of his sweets

Sara=(17-x)Sweets\\\\Tim=\frac{(24+x)Sweets}{2}

So, the expression for the number of sweets that Sara and Tim have now, are:

Sara=(17-x) Sweets\\\\Tim=\frac{(24+x)Sweets}{2}

Have a nice day!

8 0
3 years ago
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