Step-by-step explanation:
This is the answer. Hope it helps.
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer:
PEMDAS
Step-by-step explanation:
Using PEMDAS or the order of operations, you first multiply 2 by 6
2-2×6+3
2-12+3
Then you can go in any order since addition and subtraction take the same precedence.
-10+3=-7
Answer:
Step-by-step explanation:
Multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.
Or, You can simply reduce the fraction with 2, which results to 1.
Hope I helped!
Best regards! :D
