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tekilochka [14]
3 years ago
10

A Parking garage charges the rates in the table below. what is the rate of change.

Mathematics
2 answers:
Kaylis [27]3 years ago
6 0
Three divided by two
arsen [322]3 years ago
4 0

Answer with explanation:

We know that the rate of change in a function is given by :-

\dfrac{\text{Change in dependent variable}}{\text{Change in independent variable}}

Let x denotes the Number of hours and y denotes the Cost of parking .

Here , x- independent variable

y- dependent variable

Now, rate of change = \dfrac{\text{Change in y}}{\text{Change in x}}

=\dfrac{14-10}{3-1}=\dfrac{4}{2}=2

Here , the rate of change = $ 2 per hour.

Again rate of change = \dfrac{\text{Change in y}}{\text{Change in x}}

=\dfrac{16-14}{5-3}=\dfrac{2}{2}=1

Here , the rate of change = $ 1 per hour.

Since both rate of changes are not equal , it means the rate of change is not constant.

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Right isosceles ΔA B C has hypotenuse length h . DE is a midsegment with length 4 x that is not parallel to the hypotenuse. What
Kruka [31]

The perimeter of right isosceles ΔABC with midsegment DE is 16 + 8√2.

If right isosceles ΔABC has hypotenuse length h, then the two other sides are congruent.

side a = side b

Using Pythagorean theorem, c^2 = a^2 + b^2

h^2 = a^2 + b^2      a = b

h^2 = 2a^2

a = h/√2

If DE is a midsegment not parallel to the hypotenuse, then it is a segment that connects the midpoints of one side of a triangle and the hypotenuse. See photo for reference.

ΔABC and ΔADE are similar triangles.

a : b : h = a/2 : 4 : h/2

If a/2 = a/2, then b/2 = 4.

b/2 = 4

b = 8

If a = b, then a = 8.

If a = h/√2, then

8 = h/√2

h = 8√2

Solving for the perimeter,

P = a + b + h

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To learn more about midsegment: brainly.com/question/7423948

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