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almond37 [142]
3 years ago
12

Which of the following equations has the solution x= all real numbers?

Mathematics
1 answer:
Marysya12 [62]3 years ago
5 0
The answer is C
4(3-x)+6x=3x+12-x  All real numbers are solutions.
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Here is my question. Please help
Rasek [7]
6x^2 +30x - 36
6( x^2 +5x -6)
6(x^2 -x+6x-6)
6[ x(x-1) 6(x-1)]
(x-1) (x+6)
8 0
3 years ago
Which linear equations have an infinite number of solutions? Check all that apply. (x – ) = (x – left-parenthesis x minus StartF
allochka39001 [22]

Answer:

a, (x-3/7)=2/3(3/2x-9/14), and c, 12.3x – 18 = 3(–6 + 4.1x).

Step-by-step explanation:

i just answered that question

4 0
3 years ago
Read 2 more answers
Write two polynomials with a difference of 2x2 + x + 3
Anettt [7]

Answer:

The two polynomial CAN be 5x^4+5x^3+8x^2+x+6 and 5x^4+5x^3+8x^2+2x+13.

Step-by-step explanation:

Step 1: <u>Simplify the expression:</u>

2*2 + x + 3

4+x+3

x+7

Step 2: <u>Think of a random polynomial:</u>

5x^4+5x^3+8x^2+x+6

Step 3: <u>Either add your "random polynomial" by </u>x+7<u> or subtract it.</u>

<u>I want to add it so...</u>

5x^4+5x^3+8x^2+x+6+x+7

= 5x^4+5x^3+8x^2+2x+13

 Check by subtracting  5x^4+5x^3+8x^2+x+6 and 5x^4+5x^3+8x^2+2x+13.

         5x^4+5x^3+8x^2+2x+13

   -      5x^4+5x^3+8x^2+x+6

        _____________________

         0x^4 - 0x^3 -0x^2 +x +7 <em><u>or  </u></em>x+7<em><u /></em>

         

5 0
3 years ago
A=12 B=5 C=2 if you help your maked as the brainest
Afina-wow [57]
C^2+(2/3)
2^2+(2/3)
4+(2/3)
4 2/3

Final answer: 4 2/3 or 14/3 as an improper fraction
6 0
3 years ago
Read 2 more answers
Find the coordinates of midpoint F.
Mice21 [21]

Answer:

The coordinates are (0,b)

Step-by-step explanation:

Here, we want to find the coordinates of the midpoint F

as we can see, F is between A and B

we proceed to use the midpoint formula

The midpoint formula is;

(x,y) = (x1 + x2)/2, (y1 + y2)/2

(x1,y1) = (-3a, b)

(x2,y2) = (3a, b)

The substitution of these values will thus yield;

(-3a + 3a)/2, (b + b)/2

= (0/2), (2b/2)

= (0, b)

4 0
2 years ago
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