Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer: 9 associate property 8 commutative property
Step-by-step explanation:
Answer:
72
Step-by-step explanation:
The formula for surface area is SA = 2lw + 2wh + 2lh
W = width
L= length
H = height
A = 2(wl + hl + hw)
2·(6·3+2·3+2·6)
Simplify that down to get the answer 72
