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2 years ago

Irrational number between 7.7 and 7.9

Mathematics

1 answer:

Fantom [35]2 years ago

5 0

an irrational number between 7.7 and 7.9 is 7.86597594.... (forever continuing.)

an irrational number has no end and goes on forever.

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Which value for x makes the sentence true? 1/10 + x = 1/7

alexandr1967 [171]

Answer:

3/70

Step-by-step explanation:

change 1/10 and 1/7 so the denominator (bottom number) is the same. 1/10= 7/70 and 1/7= 10/70 so you need 3/70 to make the two numbers equal.

6 0

2 years ago

Which of the following is true about the expression V3*2

likoan [24]

Answer:

Step-by-step explanation:

√3 is an irrational number, 2 is a rational number.

the product of this will be 2√3 in surds form, and when pressed into the calculator will provide you with an irrational answer.

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2 years ago

Determine the intercepts of the line.

andre [41]

Answer:

x-intercepts = (-3/4, 0)

y-intercepts = (0, 3/7)

Step-by-step explanation:

3 0

2 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

Novay_Z [31]

Answer: $3+\sqrt{2}$

Step-by-step explanation:

Given the following expression shown in the picture:

$\frac{7}{3-\sqrt{2} }$

You need to use a process called "Ratinalization".

By definition, using Rationalization you can rewrite the expression in its simplest form so there is not Radicals in its denominator.

Then, in order to simplify the expression, you can follow the following steps:

Step 1. You need to multiply the numerator and the denominator of the fraction by $3+\sqrt{2}$ , which is the conjugate of the denominator $3-\sqrt{2}$ .

Step 2. Then you must apply the Distributive property in the numerator.

Step 3. You must apply the following property in the denominator: $(a+b)(a-b) = a^2 - b^2$

Therefore, applying the procedure shown above, you get:

$=\frac{(7)(3+\sqrt{2})}{(3-\sqrt{2})(3+\sqrt{2})}=\frac{21+7\sqrt{2}}{3^2-(\sqrt{2})^2}=\frac{21+7\sqrt{2}}{9-2}=\frac{21+7\sqrt{2}}{7}$

Step 4. You can observe that the expression can be simplified even more. Since:

$\frac{a+b}{c}=\frac{a}{c}+\frac{b}{c}$

You get:

$\frac{21+7\sqrt{2}}{7}=\frac{21}{7}+\frac{7\sqrt{2}}{7}=3+\sqrt{2}$

3 0

2 years ago

What value of m makes the equation true? -3m = - 12

Nina [5.8K]

Answer: m = 4

Step-by-step explanation:

-3m(4) = -12

6 0

2 years ago

Read 2 more answers