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2 years ago

6. 1 68 61 2 m21 = 3 m22= m23 -

Mathematics

1 answer:

Advocard [28]2 years ago

6 0

1 = 51

2= 61

3= 29

Step-by-step explanation:

1) 61+68= 129

180-129= 51

2) 61 is across it so they have the same number

3) 61 +90= 151

180-151= 29

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A guy wire is attached to an upright pole 6 meters above the ground. If the wire is anchored to the ground 4 meters from the bas

Dafna11 [192]

Answer:

Step-by-step explanation:

A right angle triangle is formed

The length of the guy wire represents the hypotenuse of the right angle triangle.

The ground distance between the guy wire and the pole represents the adjacent side of the right angle triangle.

The height of the pole represents the opposite side of the right angle triangle.

To determine the length of the wire, h, we would apply Pythagoras theorem

Hypotenuse² = opposite side² + adjacent side²

h² = 6² + 4²

h² = 36 + 16 = 52

h = √52

h = 7.21 meters

3 0

3 years ago

The diagram shows a right angle triangle find the size of x give your answer to 1 decimal place

Verizon [17]

Answer:

34.9°

Step-by-step explanation:

SOH

CAH

TOA

SOH ... sin(x) = 8/14

arcsin(8/14) = 34.85°

7 0

2 years ago

Answers for the 2 boxes please

almond37 [142]

Answer:

(4,9)

Step-by-step explanation:

y = 2x + 1

y = x + 5

2x + 1 = x + 5

2x - x = 5 - 1

x = 4

y = x + 5

y = 4 + 5

y = 9

Check:

(4,9) ? Yep

3 0

2 years ago

ali rented a truck for one day. there was a base fee of $18.99, and there was an additional charge of 78 cents for each mile dri

igomit [66]

Answer:

164

Step-by-step explanation:

146.91-18.99= 127.92

127.92/0.78= 164

3 0

3 years ago

. Use the process outlined in the lesson to approximate the number 3√10. Use the approximation √10 ≈3162 277 7.

GaryK [48]

Answer:

sequence of five intervals

(1) 3³ < $3^{\sqrt{10} }$ < $3^{4}$

(2) $3^{3.1}$ < $3^{\sqrt{10} }$ < $3^{3.2}$

(3) $3^{3.16}$ < $3^{\sqrt{10} }$ < $3^{3.17}$

(4) $3^{3.162}$ < $3^{\sqrt{10} }$ < $3^{3.163}$

(5) $3^{3.1622}$ < $3^{\sqrt{10} }$ < $3^{3.1623}$

Step-by-step explanation:

as per question given data

√10 ≈ 3.162 277 7

to find out

sequence of five intervals

solution

as we have given that √10 value that is here

√10 ≈ 3.162 277 7 ........................1

when we find $3^{\sqrt{10} }$ ................2

put here √10 value in equation number 2

we get $3^{\sqrt{10} }$ that is 32.27

sequence of five intervals

(1) 3³ < $3^{\sqrt{10} }$ < $3^{4}$

(2) $3^{3.1}$ < $3^{\sqrt{10} }$ < $3^{3.2}$

(3) $3^{3.16}$ < $3^{\sqrt{10} }$ < $3^{3.17}$

(4) $3^{3.162}$ < $3^{\sqrt{10} }$ < $3^{3.163}$

(5) $3^{3.1622}$ < $3^{\sqrt{10} }$ < $3^{3.1623}$

5 0

3 years ago