Log(4k - 5) = log(2k - 1)
log(4k) - log(5) = log(2k) - log(1)
0.6020599913k - 0.6989700043 = 0.3010299957k - 0
0.6020599913k - 0.6989700043 = 0.3010299957k
<u>-0.6020599913k -0.6020599913k</u>
<u>-0.6989700043</u> = <u>-0.3010299957k</u>
-0.3010299957 -0.3010299957
2.321928094 = k
Answer:
c. 441ft^2
Step-by-step explanation:
Area is height times length and since it's a square, safe to say that the sides are equal in length. So square root both of the given areas of the 2 square:
= 29
= 20
Now u have side b and c of the triangle, it's a right triangle so use the Pythagorean theorem a^2 + b^2 = c^2
a^2 + b^2 = c^2
a^2 + 20^2 = 29^2
a^2 + 400 = 841
subtract 4 from both sides
a^2 = 441
square root both sides

a = 21
Now the side a of the triangle is also a side of the small square therefore
21^2 = 441
You can expect 76 students in 2018 because from 2014 to 2015 it went up 6, then 8, then 10 so it would increase 12 students from 2017 to 2018
Answer:
A
Step-by-step explanation:
9 > 3 + 2x
6 > 2x
3 > x
or
x < 3
and that means 3 is NOT included (otherwise there must be a smaller or equal sign). hence A is the right answer.
see the attached figure to better understand the problem
we have that

Step 1
<u>Find the value of AC</u>
we know that
in the right triangle ABC

substitute the values in the formula

Step 2
<u>Find the value of BC</u>
we know that
in the right triangle ABC
Applying the Pythagorean Theorem

substitute the values

Step 3
<u>Find the value of BD</u>
we know that
in the right triangle BCD
Applying the Pythagorean Theorem

substitute the values


therefore
<u>the answer is</u>
the length of BD is 11.93 units