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natita [175]
3 years ago
8

What are tectonic plates and how do they work?

Biology
1 answer:
elena-s [515]3 years ago
7 0

Plate tectonics is the study of movement of the Earth's plates, called tectonic plates. A tectonic plate is a huge, irregularly shaped slab of solid rock. They are commonly composed of continental and oceanic lithosphere. Weather, as well as others, cause tectonic plates to slide, this causes a slight shake, volcanoes or earthquakes.



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BRAINLIESTTTT ASAP!!!<br><br> please explain your answers. :)
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Read 2 more answers
Compare and contrast the ways of life of crustaceans and arachnids and explain how their body forms are adapted to their environ
Ede4ka [16]
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6 0
3 years ago
In one type of plant, orange petals (O) are dominant over yellow petals (o) and tall stems (T) are dominant over short stems (t)
vodka [1.7K]

Answer No 1:

The set up of the punnet square is shown in the attached diagram. As the alleles assort independently hence the gametes formed will be OT,Ot,OT,Ot and OT,Ot,oT,ot. These will be the outcomes of the possible gametes formed. When these gametes are cross bred, the results are shown in the diagram attached.

Answer No 2:

The outcomes of each possible genotype are:

OOTT = 2/16

OOTt = 4/16

OOtt = 2/16

Oott = 2/16

OoTT = 2/16

OoTt = 4/16

Answer No 3:

The likelihood of each possible offspring phenotype is:

Orange petals with tall stem  and orange petals  with small stems present in ratio 12:4 i.e. 3:1.

6 0
3 years ago
The Offspring produced by a cross between two given types of plants can be any of the three genotypes denoted by A, B, and C. A
ratelena [41]

Complete question:

The offspring produced between two given types of plants can be any of the three genotypes, denoted by A, B and C. A theoretical model of gene inheritance suggests that the offspring of types A, B and C should be in a 1:2:1 ratio (meaning 25% A, 50% B, and 25% C). For experimental verification, 100 plants are bred by crossing the two given types. Their genetic classifications are recorded in the table below.

<em><u>Genotype       Observed frequency</u></em>

    A             →        18 individuals

    B             →        55 individuals

    C             →        27 individuals

Do these contradict the genetic model?  

Use a 0.05 level of significance.

Determine the chi-square test statistic.

Answer:

Do these contradict the genetic model? No, according to the chi-square test, there is not enough evidence to reject the null hypothesis of the population being in equilibrium.  

Explanation:

<u>Available data</u>:

  • Crossed genotypes: two
  • Genotypes among the offspring; Three → A, B, and C
  • Expected phenotypic ratio → 1:2:1
  • Total number of individuals, N = 100
  • A = 18 individuals
  • B = 55 individuals
  • C = 27 individuals

So, let us first state the hypothesis:

  • H₀= the population is equilibrium for this locus → F(A) = 25%,  F(B) = 50%, F(C) = 25%  
  • H₁ = the population is not in equilibrium

Now, let us calculate the number of expected individuals, according to their expected ratio.

4 -------------- 100% -------------100 individuals

1 ---------------  25% -------------X = 25 individuals A

2 --------------  50% -------------X = 50 individuals B

1----------------- 25%--------------X = 25 individuals C

<u>                                                   A                             B                           C</u>

  • Observed                         18                            55                         27
  • Expected                         25                           50                         25
  • (Obs-Exp)²/Exp                1.96                        0.5                        0.16

<u>(Obs-Exp)²/Exp</u>

A)  (18 - 25)²/25 = 49/25 = 1.96

B)  (55 - 50)² / 50 = 25/50 = 0.5

C)  (27 - 25)²/25 = 4/25 = 0.16

Chi square = X² = Σ(Obs-Exp)²/Exp  

  • ∑ is the sum of the terms
  • O are the Observed individuals: 2 in chamber B, and 18 in chamber A.  
  • E are the Expected individuals: 10 in each chamber  

X² = ∑ ((O-E)²/E) = 1.96 + 0.5 + 0.16 = 2.62

Freedom degrees = 2

Significance level, 5% = 0.05  

Table value/Critical value = 5.99

X² < Critical value

2.62 < 5.99    

<em>These results suggest that there is </em><u><em>not enough evidence to reject</em></u><em> the null hypothesis. We can assume that </em><u><em>the locus under study in this population is in equilibrium H-W.  </em></u>

 

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3 years ago
A substance with pH of 6 is called an?
Nady [450]
A substance with pH 6 would be an acid, because it's 1pH to the left of a neutral substance
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