All categories

3 years ago

Which applies the power of a product rule to simplify (5t)^3?

Mathematics

2 answers:

Gennadij [26K]3 years ago

6 0

Answer:

$125t^{3}$

Step-by-step explanation:

The power product is given by the following formula:

$(ab)^{x} = a^{x}*b^{x}$

In this case, this gives us:

$(5t)^{3} = (5)^{3} * t^{3}$

= $125*t^{3}$

= $125t^{3}$

frozen [14]3 years ago

5 0

$(5t)^3 = 125t^3$

You might be interested in

Help.. please... my due is in 5 minutes

Diano4ka-milaya [45]

<h3>Answer:</h3>

y = x - 5

<h3>Step-by-step explanation:</h3>

If 5 is being subtracted from x, then it would look like x-5.

Since x-5 represents 5 being subtracted from x, y=x-5 is the correct answer because the other options aren't representing 5 subtracted from x.

3 0

2 years ago

If A and B are independent events, P(A) = 0.25, and P(B) = 0.3, what is P(AB)?

Marrrta [24]

Answer:

$P(A) = 0.25, P(B= 0.3$

And if we want to find $P(A \cap B)$ we can use this formula from the definition of independent events :

$P(A \cap B) =P(A) *P(B) = 0.25*0.3= 0.075$

And the best option would be:

$P(A \cap B) =0.075$

Step-by-step explanation:

For this case we have the following events A and B and we also have the probabilities for each one given:

$P(A) = 0.25, P(B= 0.3$

And if we want to find $P(A \cap B)$ we can use this formula from the definition of independent events :

$P(A \cap B) =P(A) *P(B) = 0.25*0.3= 0.075$

And the best option would be:

$P(A \cap B) =0.075$

3 0

3 years ago

The product of 12 and k is 84.<br><br> Solve for k.

Mrac [35]

Answer:

The product of 12 and k is 84

According to the given problem, the equation is

$\boxed{12k = 84} \\ k = \frac{84}{12} \\ \boxed{k = 7}$

<u>k = 7</u> is the right answer.

5 0

3 years ago

A number is chosen at random from 1 to 50. find the probability of selecting numbers with 3 in the tens places

andrew-mc [135]

5/50 =.1 or 10% or 1/10

3 0

4 years ago

X<br> 41<br> 40<br> What’s the answer

Nina [5.8K]

Answer:

Papi

Step-by-step explanation:

3 0

3 years ago