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cupoosta [38]
3 years ago
9

Which applies the power of a product rule to simplify (5t)^3?

Mathematics
2 answers:
Gennadij [26K]3 years ago
6 0

Answer:

125t^{3}

Step-by-step explanation:

The power product is given by the following formula:

(ab)^{x} = a^{x}*b^{x}

In this case, this gives us:

(5t)^{3}  = (5)^{3} * t^{3}

        = 125*t^{3}

        = 125t^{3}

frozen [14]3 years ago
5 0
(5t)^3 = 125t^3
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We reject our null hypothesis, H₀, at a level of significance of =0.01 since the P-value is less than that threshold. There is compelling statistical data to indicate that since 1991, the proportion of drivers who love driving has decreased.

Given,

The Pew Research Center recently polled n=1048 U.S. drivers and found that 69% enjoyed driving their automobiles.

In 1991, a Gallup poll reported this percentage to be 79%. using the data from this poll, test the claim that the percentage of drivers who enjoy driving their cars has declined since 1991.

To report the large-sample z statistic and its p-value,

Null hypothesis,

H₀ : p = 0.79

Alternative hypothesis,

Ha : p < 0.79

Level of significance, α = 0.01

Under H₀

Test statistic,

Z_0= \frac{\hat p - p}{\sqrt{\frac{p(1-p)}{n} }  }

Z₀ = -7.948

The alternative hypothesis(Ha) is left-tailed, so the P-value of the test is given by

P-value = P(z <-7.945)

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Since the P-value is smaller than given level of significance, α=0.01 we reject our null hypothesis, H₀, at α=0.0.1 level Strong statistical evidence to conclude that the percentage of drivers who enjoy driving their cars has declined since 1991.

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PlZZZ HELP<br><br> Which of the following is equal to
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Answer:

1st option

Step-by-step explanation:

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The amount that is the closest to the account balance at the end of 4 years is given by: Option B: $5,860. 53 (approx)

<h3>How to calculate compound interest's amount?</h3>

If the initial amount (also called as principal amount) is P, and the interest rate is R% per unit time, and it is left for T unit of time for that compound interest, then the interest amount earned is given by:

CI = P(1 +\dfrac{R}{100})^T - P

The final amount becomes:

A = CI + P\\A = P(1 +\dfrac{R}{100})^T

For the considered case, we're given that:

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The final amount at the end of 4 years in the considered account of Laura is evaluated as:

A = 5500(1 + \dfrac{1.6}{100})^4 = 5500(1.016)^4  \approx 5860.53 \: \rm (in \:  dollars)

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The end behavior of a function f tells us that the way that the graph function behaves at the "ends" of the x-axis.

Note that the end behavior of a function tells the trend of the graph and in this graph, f(x) -----> +∞ as x----> -∞  (as the value of x decreases the value of f(x) increases) and  f(x) -----> -∞ as x----> +∞ (as the value of x increases the value of f(x) decreases).

Therefore, The end behavior of the graph of f(x) = -0.25x2 - 2x + 1 is that A) As x increases, f(x) increases. As x decreases, f(x) decreases.

See full question below

What is the end behavior of the graph of f(x) = -0.25x2 - 2x + 1?

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C) As x increases, f(x) increases. As x decreases, f(x) increases.

D) As x increases, f(x) decreases. As x decreases, f(x) increases

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