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2 years ago

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Please help me with this

1 answer:

Naddika [18.5K]2 years ago

7 0

2x^2 -7x + 14 =0 is the standard form

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A line with slope 6.5 and y-intercept (0,-8)

nika2105 [10]

Answer:

The equation would be y = 6.5x-8

Step-by-step explanation:

6 0

2 years ago

The world's most powerful tugboats are built in Finland. One of these boats can do 9.8 × 107 J of work through a distance of 35

kkurt [141]

<span>2.8 x 10^6 N We have 9.8 x 10^7 J or 9.8 x 10^7 kg*m^2/s^2 of work done through a distance of 35 meters. Since work is defined as force over distance, that means that: F * 35m = 9.8 x 10^7 kg*m^2/s^2 Solving for F, gives F * 35m = 9.8 x 10^7 kg*m^2/s^2 F = 9.8 x 10^7 kg*m^2/s^2 / 35m F = 2.8 x 10^6 kg*m/s^2 F = 2.8 x 10^6 N So the force exerted by the tugboat is 2.8x10^6 Newtons.</span>

3 0

3 years ago

8(5g+5−2) Distributive Property to simplify the expression.

denpristay [2]

Answer:

= 40g -24

Step-by-step explanation:

you would multiply everything in the bracket by 8 to expand this

e.g.

(8x5g )+ (8x5 )+ (8 x -2)

= 40g + 40 - 16

now simplify by subtracting the like terms

= 40g -24

7 0

2 years ago

The manager of a fast-food restaurant determines that the average time that her customers wait for service is 3.5 minutes.The ma

Lana71 [14]

Answer:

The advertisement should use 16 minutes.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The manager of a fast-food restaurant determines that the average time that her customers wait for service is 3.5 minutes.

This means that $m = 3.5, \mu = \frac{1}{3.5} = 0.2857$

What number of minutes should the advertisement use?

The values of x for which:

$P(X > x) = 0.01$

So

$e^{-\mu x} = 0.01$

$e^{-0.2857x} = 0.01$

$\ln{e^{-0.2857x}} = \ln{0.01}$

$-0.2857x = \ln{0.01}$

$x = -\frac{\ln{0.01}}{0.2857}$

$x = 16.12$

Rounding to the nearest number, the advertisement should use 16 minutes.

5 0

3 years ago

A pyramid has a square base with side s. the hight of the pyramid is 2/3 that of its side. What expression for the volume of the

Bess [88]

i have no clue sorry i cant help you :)

6 0

3 years ago