It's C, just look at where the points are.
Answer :
no. of days used to repair 1250m of road = 5
no. of days used to repair 1m of road = 5/1250
no. of days used to repair 8000m of road (8*1000m ) = 5/1250*8000= 32 days
Answer:
i believe is is 3/2
Step-by-step explanation:
as y goes up 30 x goes over 20
30/20 simplified is 3/2
Answer:
-74x^2
Step-by-step explanation:
-2x x 5x -(8x)^2
-10x^2-(8x)^2
-10x^2-64x^2
-74x^2
The answer is 270 trucks.
