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tigry1 [53]
3 years ago
14

A particular hybrid car travels approximately 204 mi on 4 gal of gas. Find the amount of gas required for a 714​-mi trip.

Mathematics
1 answer:
77julia77 [94]3 years ago
6 0
I think its 13.1 gallons for a 714 mile trip
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3x−8 ≤ 23 OR −4x+26≥6 find x
ElenaW [278]

Answer:

3x-8<=23

3x<=23+8

3x< =31

X< = 10.3

or

-4x+26>=6

-4x>=-20

X>=5

6 0
3 years ago
Need help on this question. Will give brainliest
Llana [10]

Answer: C

Step-by-step explanation:

Bcuz when its square it results to something known as the perfect square trinomial. Thats the way i learned it. Ion know if u learned it the same way pero i hope this helps.

3 0
2 years ago
Help. Also, how do you give Brainliest?
lawyer [7]

Okay so basically when two people answer your questions it should give you the option to give brainliest otherwise sometimes it takes a few days to give it to someone. And for your question does it give any number options.?

Edit: f(-1)= 1 then f(1)= -10.

4 0
3 years ago
Read 2 more answers
Calls to a customer service center last on average 2.8 minutes with a standard deviation of 1.4 minutes. An operator in the call
Natali5045456 [20]

Answer:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n-values of normal variable:

Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is M = n\mu and the standard deviation is s = \sigma\sqrt{n}

Calls to a customer service center last on average 2.8 minutes.

This means that \mu = 2.8

75 calls each day.

This means that n = 75

What is the expected total amount of time in minutes the operator will spend on the calls each day

This is M, so:

M = n\mu = 75*2.8 = 210

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

6 0
3 years ago
What is the perimeter of the rectangle? Write your answer in scientific notation. The area is 2.76 x 10 pw12 the width is 4.6 x
Elanso [62]
The caret (^) is the symbol conventionally used to indicate an exponent.

You have
  area = 2.76·10^12
  width = 4.6·10^5

You want to find the perimeter of the rectangle with these dimensions.

The perimeter of a rectangle is twice the sum of length and width.
  perimeter = 2*(length + width)
The length can be figured from the area using the formula for area.
  area = length*width
  area/width = length . . . . . . . . . divide by width
Filling in the numbers, we have
  perimeter = 2*((2.76·10^12)/(4.6·10^5) +(4.6·10^5))
  perimeter = 2*(6.0·10^6 +0.46·10^6)
  perimeter = 2*6.46·10^6 = 1.292·10^7

The perimeter of the rectangle is ...
  1.292·10^7
6 0
3 years ago
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