Answer:82+31=113 180-113=67 so the answer is 67
Step-by-step explanation:
Volume of a cylinder is
, where r is the radius and h is the height.
This comes from the area of a circle being
. A cylinder is the area of the base circle multiplied by its height.
Using this formula, the volume of the given cylinder is
Answer:
y = 8x
Step-by-step explanation:
Given that :
Ornanment are packed in boxes
Number of ornament per box = 8
x = number of boxes packed
y = Number of ornaments
Number of Ornanments packed = (Number ornaments per box * number of boxes packed
y = 8 * x
y = 8x
We will initially rewrite the expression provided for the sake of clarity:
(9 x 10⁵)(6 x 10⁻⁷)
The simplify this type of expression, we must follow the order of operations. We can use the acronym BEDMAS to help us with this problem. BEDMAS refers to the order that mathematical operations take place and states that you first solve whatever is inside brackets (in this case parentheses). This is followed by addressing any exponents. After brackets and exponents it is division and multiplication that take place. Division and multiplication are interchangeable and can take place in either order. The same can be said for addition and subtraction which is the last operation, but each is interchangeable. Following these rules we can solve this expression:
We do not need to solve anything within the parentheses since we are asked to leave the problem in scientific notation. Scientific notation is of the form n x 10ˣ. We do not need to address the exponents either as they are a part of the scientific notation. Next we move on to multiplication which is multiplying the two numbers inside the parentheses.
(9 x 10⁵)(6 x 10⁻⁷)
We can multiply all of these terms in any order. To simplify, we can multiply both exponents as they have the same base numbers.
(9 x 6) (10⁵ x 10⁻⁷)
(54)(10⁻²)
54 x 10⁻²
5.4 x 10⁻¹
When multiplying exponents with the same base, we can add the exponents, and then multiply the rest of the terms and this provides us with option 2 as the answer.
