Answer:
Boiling point of jet fuel = 165 degrees Celsius
Step-by-step explanation:
Given:
Boiling point of jet fuel = 329°F
Find:
Boiling point of jet fuel in degrees Celsius
Computation:
C = [5/9][F – 32]
C = [5/9][329 – 32]
C = 165
Boiling point of jet fuel = 165 degrees Celsius
145-132= 13
13/145 = 0.089655 rounded to 9
9%
Answer:
1100/54 yds
Step-by-step explanation:
First convert inches and feet to yards
[3 ft = 1 yd, 12in = 1yd]
5ft = 1 2/3 yds
6in = 1/6 yds
220ft = 73 1/3 yds
Now use the volume formula,
b*w*h = A
[1 2/3] * [1/6] * [73 1/3]
= [5/3] * [1/6] * [220/3]
= [5/18] * [220/3]
= 1100/54 yds
5x²y³ is the GCF
5 is the GCF of 10 and 15, to find the GCF of the variables, take the lowest exponent power of each of the variables
