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garik1379 [7]
3 years ago
7

Can somebody tell me the answer to this please​

Mathematics
1 answer:
ahrayia [7]3 years ago
7 0
C is 2,2 D 2,6 E 6,5 alway use the x-axis
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The width of the rectangle is 7 feet, and the diagonal length of the rectangle is 16 feet. which measurement is the closest to t
yanalaym [24]

Answer: b. 14ft

Step-by-step explanation:

In the rectangle, the opposite sides are equal. The diagonal divides the rectangle into two equal right angle triangles. The diagonal represents the hypotenuse of both right angle triangles. The length and width represents the opposite and adjacent sides of the right angle triangles.

To determine the length, L of the rectangle, we would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

Therefore,

16² = L² + 7²

256 = L² + 49

L² = 256 - 49 = 207

L = √207

L = 14.38

the closest to the length of this rectangle in feet is

14ft

3 0
3 years ago
Read 2 more answers
What is the zeros of the quadratic function y=x^2+14x+24
777dan777 [17]

Step-by-step explanation:

{x}^{2}  + 14x + 24 = 0 \\  {x}^{2}  + 12x + 2x + 24 = 0 \\ x(x + 12) + 2(x + 12) = 0 \\ (x + 12)(x + 2)  = 0\\ x =  - 12 \\ x =  - 2

6 0
3 years ago
Choose a number between 67 and 113 that is a multiple of 3, 9, and 12
Anestetic [448]
72 is multiples of 3,9, and 12
3 0
3 years ago
Please help!! 20 POINTS
rjkz [21]

f(-3) would be 36.

When looking at synthetic division, the numbers across the top represent the coefficients of x^2, x and the constant in that order. Therefore, the equation is as follows.

2x^2 - 5x + 3

Now we can put -3 into the equation and solve.

2(-3)^2 - 5(-3) + 3

2(9) + 15 + 3

18 + 15 + 3

36

7 0
3 years ago
My brother is in 6th grade and needs help with his math. I tried to help but I can't find any answers on it.
In-s [12.5K]

Answer:

Question 1) 17.4

Question 2) 1.7

Question 3) 2.8

Question 4) 8.6

Step-by-step explanation:

Mean absolute deviation is the average distance between the data points from the set to the mean point of the data set. It shows the variability in data or how much the data points are spread.

method to calculate Mean absolute deviation:

a. calculate mean

b. calculate absolute deviation of each data point

c. add all the deviations

d. divide absolute deviation by number of points

mean absolute deviation = ∑lx_{i}-xl / n

The given problem has four sub-parts

Solution 1:

Mean= (78+99+90+80+55+56+102+88+60+42)/10

            =  750/10

            =  75

Mean absolute deviation= ( I 78-75 I + I 99-75 I+I 90-75 I + I 80-75 I +

                                             I 55-75 I + I 56-75 I + I 102-75 I + I 88- 75 I +

                                             I 60-75 I + I 42-75 I) /10

         =  (174)/10

        =  17.4

Solution 2:

Mean = (10+13+7+12+9+8+12+10+11+13)/10

              =  (105)/10

              = 10.5

Mean absolute deviation = ( I 10-10.5 I + I 13-10.5 I + I 7-10.5 I + I 12-10.5 I +

                                              I 9-10.5 I + I 8-10.5 I + I 12-10.5 I + I 10-10.5 I +

                                               I 11-10.5 I + I 3-10.5 I) /10

       =   17/10

       = 1.7

Solution 3:

Mean= (1+7+10+5+3+3+6+12+9+4)/10

            =  60/10

            =  6

Mean absolute deviation  = ( I 1-6 I + I 7-6 I + I 10-6 I + I 5-6 I + I 3-6 I +

                                               I 3-6 I + I 6-6 I + I 12- 6 I + I 9-6 I + I 4-6 I) /10

         = (28)/10

        =  2.8

Solution 4:

Mean= (30+46+25+45+18+25+15+32+40+24)/10

            =  300/10

            =  30

Mean absolute deviation  = ( I 30-30 I + I 46-30 I + I 25-30 I + I 45-30 I +

                                               I 18-30 I + I 25-30 I + I 15-30 I + I 32-30 I +

                                               I 40-30 I + I 24-30 I) /10

         = (86)/10

        =  8.6

!

8 0
3 years ago
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