Solve for g. -3+5+6g=11-3g−3+5+6g=11−3g
1 answer:
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According to Remainder Theorem for the polynomials, for every polynomial P(x) there exist such polynomials G(x) and R(x), that .
When the polynomial in P(x) is divided by (x + a), then there exist such polynomials G(x) and R(x), that P(x)=(x+a)G(x)+R(x). Note that for x=-a:
This means that P(-a) is the remainder, not P(a). <span>
</span><span>Answer:<span> correct choice is B.</span></span>