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AlexFokin [52]
3 years ago
13

If the mass of a proton is 2.53 x 10^-37 gram, what is the mass of 1,000 protons

Mathematics
1 answer:
Dmitrij [34]3 years ago
3 0
We can solve this problem by the rule of three.

1000 protons=10³ protons

1 proton------------------2.53*10⁻³⁷g
10³ protons----------   x

x=(10³ protons  *   2.53*10⁻³⁷) / 1 proton=2.53*10⁻³⁷⁺³ protons=
=2.53*10⁻³⁴ protons

answer: 2.53*10⁻³⁴ protons
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On the farm, rather than use money, they exchange animals. The exchanges are as follows: 4 bunnies = 3 chickens, 5 chickens = 2
Radda [10]

We have to trade 5 bunnies for a donkey.

Solution:

To calculate how many bunnies could be exchanged for a donkey, we have to multiply the exchange rates of each animal/bird.

One bunny = 3/4 chickens (0.75 chicken),

One chicken = 2/5 pigs (0.4 pigs)

One pig = 2/3 donkeys (0.67 donkeys).

On multiplying all of the above rates we get,

0.75*0.4*0.67=0.2

Since we now know a bunnies worth is 0.2 donkey

Therefore, (1/0.2=5) 5 bunnies to trade for a donkey.

4 0
4 years ago
Solve for n<br> -18 = 6<br> 3
mihalych1998 [28]

Answer:

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Step-by-step explanation:

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7

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6 0
4 years ago
Read 2 more answers
Please help I will mark brainlist if correct
Setler79 [48]
Y = 3x + 13

You can get this by using the same slope and then plugging into the equation to find the intercept. <span />
8 0
3 years ago
Factor completely. <br> -3x^2+9x+30
STatiana [176]

Answer:

− 3 ( x − 5 ) ( x + 2 ) hope this helps

Step-by-step explanation:

6 0
2 years ago
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Tickets for the community fair cost $12 for adults and $5 dollars for children. On the first day of the fair, 312 tickets were s
givi [52]

With this information we can set up 2 equations:

x + y = 312      (# of tickets sold for adults + # of tickets sold to adults = 312)

12x + 5y = 2204 ( # of tickets sold for adults times $12 + # of tickets sold to adults times $5  = $2204)

Where x is how many  tickets were sold to adults and y how many tickets were sold to children

Now we can solve this system of equations by substitution:

isolate y in the first equation to find its value and plug it in the second equation

x + y = 312

isolate y by subtracting x from both sides:

x - x + y = 312

y = 312 - x

Apply y = 312 - x to the second equation

12x + 5y = 2204

12x + 5( 312 - x) = 2204

12x + 1560 - 5x = 2204

7x + 1560 = 2204

Subtract 1560 from both sides to isolate x

7x + 1560 - 1560 = 2204 - 1560

7x = 644

Divide both sides by 7

7/7x = 644/7

x = 92

Now plugin 92 for x in the first equation to find the value of y

x + y = 312

92 + y = 312

subtract 92 from both sides

92 - 92 + y = 312 - 92

y = 220

x = 92, y = 220

92 tickets were sold to adults and 220 tickets were sold to children

Hope it helps :)

Branliest would be appreciated

6 0
3 years ago
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