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Basile [38]
2 years ago
14

Help I need help I need answers by today someone please help me

Mathematics
1 answer:
Ganezh [65]2 years ago
4 0

Answer:

C.

Step-by-step explanation:

ik this because i have done this

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Find the measure of ∠COB in the figure. answers: A) 24° B) 48° C) 72° D) 132°
jasenka [17]

Answer: 48

Step-by-step explanation: COB and DOA are vertical angles. This means the two of them have the same measure. Because we know the measuremen of DOA, we can easily find the measuremen for COB since these angles are the same, so COB is 48 degrees.

7 0
3 years ago
Without dividing or multiplying, explain why 0.8 divided by 0.7 is greater
Art [367]

Answer:

It is greater because when you divide decimals you move the decimal which would automatically make the product less than the quotient.

Step-by-step explanation:

3 0
3 years ago
I need the steps for 38
jasenka [17]
Ok so first, you put the sides into a ratio. The question says that triangle GKNM is congruent to triangle VRPT. From this, we know that side GK is congruent to VR. So, we write that as a ratio. Also, we know that KN is congruent to RP. We also write that as a ratio. Then, using equations, we solve for x. But, we aren't done yet; the expression for side KN is 3x-2 and, we already know that x is equal to 4.4
So, we do 3*4.4-2 which is 11.2. Therefore, side KN is equal to 11./2Then, the expression for side RP is x+4. We already know that x is equal to 4.4. So, we do 4.4+4 which is 8.4. Therefore, side RP is equal to 8.4.
Oh, and the scale factor is 4:3 or 1.33 because you do 8.4/6.3 ( you can also do 11.2/8.4)
hope this helps ;)

8 0
3 years ago
Which statement is true about the value of the expression below?
lesantik [10]
It’s between 0 and 1
6 0
3 years ago
Simplify completely sqrt of 20Y^8
brilliants [131]

Answer:

Final answer is 2y^4 \sqrt{5}.

Step-by-step explanation:

Given expression is \sqrt{20y^8}.

Now we need to smplify the given expression \sqrt{20y^8}.

So begin with factoring 20 into two parts so that one part is perfect square number.

\sqrt{20y^8}

=\sqrt{4 \times 5y^8}

=\sqrt{4 y^8} \times \sqrt{5}

=2y^4 \times \sqrt{5}

Hence final answer is 2y^4 \sqrt{5}.

3 0
3 years ago
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