Sound intensity corresponding to 80 dB:
Step-by-step explanation:
The decibel of a normal conversation is 60 dB, which corresponds to an intensity of . (1)
The formula to use that relates the intensity of the sound in to the sound level in decibel is
Where
is the sound level in decibel
is the intensity
We can found by plugging in the numbers of (1):
Which corresponds to a sound level of 0 decibel.
Now we can find the intensity that corresponds to a sound level of
And from the equation we find:
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Answer:
55.43 meters
Step-by-step explanation:
You can use the Pythagorean Theorem for this problem. 23.11 squared is 534.07. 50.38 squared is 2537.14. When you add these answers up, you get 3072.21, which is c^2. When you take the square root of this number, you get 55.43.
Answer:
a) shrinking vertically by ½ and shifting 2 units upwards will map t² onto C
b) stretch C by factor 9/5 and shift the graph 32 units upwards
F(t) = (9/5)[½t² + 2] + 32
F(t) = 0.9t² + 3.6 + 32
F(t) = 0.9t² + 35.6
The top right one is best fit