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Virty [35]
3 years ago
9

Are the following numbers rational or irrational? 6. a) 14/20 b) 5.243 c) 0.25255255525555255555 ...

Mathematics
1 answer:
kozerog [31]3 years ago
4 0

Answer:

Step-by-step explanation:

A) rational because it’s a fraction

B) rational because it’s a fraction

C) irrational because it’s never ending

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16 points<br> 1) Write the following in standard form (answer). *<br> 4^5
m_a_m_a [10]

Answer:

1024

Step-by-step explanation:

You could put 4^5 into your calculator. It’s 4*4*4*4*4= 1024

3 0
3 years ago
Wholesale cost of a telescope: $199.50; Markup: 50%, Discount: 30%,
kupik [55]

Answer:

$2147.85

Step-by-step explanation:

199.5*.5=99.75

199.5+99.75=299.25

299.25*.3=89.775

299.25-89.775=209.475

209.475*.04=8.279

209.475+8.379=217.854

7 0
3 years ago
PLEASE ANSWER THESE I RLLY NEED HELP I DONT UNDERSTAND I WILL MARK YOU AS BRAINLIEST IF YOU ANSWRR CORRECTLY PLS AND TY​
faust18 [17]

Answer:

Step-by-step explanation:

5.  You are asked to write an equation of the line in slope-intercept form, so you need to determine the slope of the line and the y-intercept.

You're lucky. One of the points, (0,1), has an x-coordinate of 0, so you know that the y-intercept is 1.

Use the coordinates of the points to determine the slope of the line.

slope = (difference in y-coordinates)/(difference in x-coordinates) = (10-1)/(3-0) = 9/3 = 3

The slope-intercept equation of the line is  y = 3x+1

:::::

7. When x = 0, function A = 0 and function B = 3, so function B has a greater initial value.

7 0
3 years ago
The price of 3 books is Rs.330 . How many such books can be bought for Rs.550 ?
AysviL [449]
330/3= 110
550/110=5

Answer is 5 books
5 0
3 years ago
Read 2 more answers
Find an equation of the plane orthogonal to the line
jolli1 [7]

The given line is orthogonal to the plane you want to find, so the tangent vector of this line can be used as the normal vector for the plane.

The tangent vector for the line is

d/d<em>t</em> (⟨0, 9, 6⟩ + ⟨7, -7, -6⟩<em>t </em>) = ⟨7, -7, -6⟩

Then the plane that passes through the origin with this as its normal vector has equation

⟨<em>x</em>, <em>y</em>, <em>z</em>⟩ • ⟨7, -7, -6⟩ = 0

We want the plane to pass through the point (9, 6, 0), so we just translate every vector pointing to the plane itself by adding ⟨9, 6, 0⟩,

(⟨<em>x</em>, <em>y</em>, <em>z</em>⟩ - ⟨9, 6, 0⟩) • ⟨7, -7, -6⟩ = 0

Simplifying this expression and writing it standard form gives

⟨<em>x</em> - 9, <em>y</em> - 6, <em>z</em>⟩ • ⟨7, -7, -6⟩ = 0

7 (<em>x</em> - 9) - 7 (<em>y</em> - 6) - 6<em>z</em> = 0

7<em>x</em> - 63 - 7<em>y</em> + 42 - 6<em>z</em> = 0

7<em>x</em> - 7<em>y</em> - 6<em>z</em> = 21

so that

<em>a</em> = 7, <em>b</em> = -7, <em>c</em> = -6, and <em>d</em> = 21

4 0
3 years ago
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