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Anna11 [10]
3 years ago
7

How many times greater is the capacity of one cup than one fluid ounce

Mathematics
1 answer:
IrinaK [193]3 years ago
6 0
My answer -

Cup= 8 fl.o.z 1 pint = 2 c .

P.S

Have an AWESOME!!! day :)
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Liula [17]

Why did the narrator use the phrase “fit together like puzzlec pieces” to describe how the cells of a developing human embryo form a human face            

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3 years ago
Please find the general limit of the following function:
valentinak56 [21]

Answer:

The general limit exists at <em>x</em> = 9 and is equal to 300.

Step-by-step explanation:

We want to find the general limit of the function:

\displaystyle \lim_{x \to 9}(x^2+2^7+(9.1\times 10))

By definition, a general limit exists at a point if the two one-sided limits exist and are equivalent to each other.

So, let's find each one-sided limit: the left-hand side and the right-hand side.

The left-hand limit is given by:

<h3>\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1 \times 10))</h3>

Since the given function is a polynomial, we can use direct substitution. This yields:

=(9)^2+2^7+(9.1\times 10)

Evaluate:

300

Therefore:

\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1 \times 10))=300

The right-hand limit is given by:

\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))

Again, since the function is a polynomial, we can use direct substitution. This yields:

=(9)^2+2^7+(9.1\times 10)

Evaluate:

=300

Therefore:

\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))=300

Thus, we can see that:

\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1\times 10))=\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))=300

Since the two-sided limits exist and are equivalent, the general limit of the function does exist at <em>x</em> = 9 and is equal to 300.

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
On a map, 90 miles is represented by 3 inches.
zepelin [54]
Hello!

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3 / 0.5 = 6

So they divide it by 6

We do 90/6

90/6 = 15

The answer is 15

Hope this helps!
7 0
4 years ago
Which fraction below represents a terminating decimal?<br> A. <br> B. <br> C. <br> D.
Vsevolod [243]

Answer:

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