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STALIN [3.7K]
3 years ago
13

The segments shown below could form a triangle.​

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
6 0
False beacause they are tooo short
Triss [41]3 years ago
4 0

Answer:

False

Step-by-step explanation:

It's been a while since I did this but here we go:

So to find if the triangle lengths are possible, we take the shorter two lengths and we add them.

Those shorter two lengths sum have to be <em>greater</em> than the longest length.

I hope this helps.

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Please help meeeeeeeeeeeeeeeeeeeeeeeeeeeee
natulia [17]

Answer:

77 m (nearest metre)

Step-by-step explanation:

<u>Angle of Elevation</u>

If a person stands at a point and looks up at an object, the angle between their <u>horizontal line of sight</u> and the <u>object</u> is called the angle of elevation.

To find how tall the flagpole is, model as a right triangle and solve using the tan trigonometric ratio.

<u>Tan trigonometric ratio</u>

  \sf \\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given information:

  • Person height = 1.6 m
  • Horizontal distance (from person to flagpole) = 35 m
  • Angle of elevation = 65°

Therefore:

  • \theta = 65°
  • O = height of flagpole <u>less</u> height of person
  • A = 35 m

As the person is 1.6 m tall, we model the line of sight as 1.6 m <u>above ground level</u>.  Therefore, when calculating the height of the flagpole, we will need to add the height of the person to the value found using the trig ratio.

Substitute the given values into the formula and solve for O:

\implies \sf \tan(65^{\circ})=\dfrac{O}{35}

\implies \sf O=35\tan(65^{\circ})

Therefore the height of the flagpole is:

\implies \sf 35\tan(65^{\circ})+1.6=76.65774222...

\implies \sf Height\:of\:flagpole=77\:m\:(nearest\:metre)

Learn more about Angles of Elevation here:

brainly.com/question/27933160

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