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lozanna [386]
4 years ago
7

Which is a factor of x4 + 8x - 48? O (X-6) 0 (x + 4) 0 (x - 16) (x + 12)

Mathematics
1 answer:
OverLord2011 [107]4 years ago
4 0

Answer:

(x+12)

Explanation:

You can factor this problem out as (x+12)(x-4), so (x+12) is a factor.

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Which property is used in the following pression? 4(5 + 7) = 20 + 28
EleoNora [17]

Answer:

Distributive property

Explanation:

You are distributing 4 to (5 + 7) by multiplying 4 by both numbers.

6 0
4 years ago
Simplify: Negative two and one-third minus negative ten and one-sixth
Eduardwww [97]

Answer:

1.\rightarrow -2 \frac{1}{3}-(-10) \frac{1}{6}\\\\\rightarrow \frac{-7}{3} -\frac{-61}{6}\\\\\rightarrow \frac{-14+61}{6}\\\\\rightarrow \frac{47}{6}\\\\\rightarrow 7\frac{5}{6}

Option C→Seven and five-sixths

2.

(-3) +(-5)

Mark -3 and -5 on the number line.Move 5 units left of -3 to reach at -8.That is required sum.

3.

Distance between −12 and −15 on the number line is given by

       |-12 -(-15}| or |-15 -(-12)|

=|-12+15| or |-15+12|

=|3| or |-3|

=3 units

Option C

|−12 − (−15)| = 3

8 0
3 years ago
7401divied by 4 pls help me
Vadim26 [7]

Answer:

1852.5 your right answers

4 0
2 years ago
Approximate the change in the volume of a sphere when its radius changes from r​ = 40 ft to r equals 40.05 ft (Upper V (r )equal
alexgriva [62]

Answer:

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

Step-by-step explanation:

The volume of the sphere (V), measured in cubic feet, is represented by the following formula:

V = \frac{4\pi}{3}\cdot r^{3}

Where r is the radius of the sphere, measured in feet.

The change in volume is obtained by means of definition of total difference:

\Delta V = \frac{\partial V}{\partial r}\Delta r

The derivative of the volume as a function of radius is:

\frac{\partial V}{\partial r} = 4\pi \cdot r^{2}

Then, the change in volume is expanded:

\Delta V = 4\pi \cdot r^{2}\cdot \Delta r

If r = 40\,ft and \Delta r = 40\,ft-40.05\,ft = 0.05\,ft, the change in the volume of the sphere is approximately:

\Delta V \approx 4\pi\cdot (40\,ft)^{2}\cdot (0.05\,ft)

\Delta V \approx 1005.310\,ft^{3}

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

7 0
3 years ago
If a figure has a scale factor of 2 it is an
bonufazy [111]
The question isn’t clear but If you’re talking about triangles then it would be an enlargement
5 0
3 years ago
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