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3 years ago

Help please hurry need help

Mathematics

1 answer:

Misha Larkins [42]3 years ago

5 0

Answer:

1: D

2: B

3: y=-4x+22

4: y=-8x+26

Step-by-step explanation:

1: Parallel lines have the same slope, and the only one with a slope of 3x is D

2: Perpendicular lines have an opposite slope, so a line with a slope of -1/2 would be 2, so you just flip the number and add or take away a negative sign, depending on the original slope

3: Like I said before, perpendicular lines have an opposite slope, so the slope would be -4. After you've figured that out, you just plug in the numbers given to you (and remember, x is first, y is last)

Plug in: 6=-4(4)+b

You would then solve for b.

6=-16+b

22=b

Then plug that into y=mx+b, with m being the slope (-4) and b being the y intercept (22)

4: The process for finding parallel and perpendicular lines is very similar, except you don't have to change the slope.

Plug in: 10=-8(2)-b

10=-16+b

26=b

Again, plug that into the equation y=mx+b

Hope I could be of help! Sorry if it doesn't make sense, this is my first time on this website.

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3 years ago

to support a tree damaged in a storm, a 12-foot wire is secured from the ground to the tree at a point 10 feet off the ground. t

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Choice given:
33.6°
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SinΘ = 10/12
SinΘ = 0.83

I used the calculator to get the value of each angle using the sine function
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The angle where the wire meets the ground is approximately 56.4°

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3 years ago

Read 2 more answers

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3 years ago

Find the slope of the tangent line to the given polar curve at the point specified by the value of θ

MariettaO [177]

The given curve has equation

r(θ) = 9 + 8 cos(θ)

and its derivative is

dr/dθ = -8 sin(θ)

When θ = π/3, we have r (π/3) = 13, and dr/dθ (π/3) = -4√3.

Differentiate these with respect to θ :

dy/dθ = dr/dθ sin(θ) + r(θ) cos(θ)

dx/dθ = dr/dθ cos(θ) - r(θ) sin(θ)

In polar coordinates, we have

y(θ) = r(θ) sin(θ)

x(θ) = r(θ) cos(θ)

and when θ = π/3, we have y (π/3) = 13√3/2 and x (π/3) = 13/2.

The slope of the tangent line to the curve is dy/dx. By the chain rule,

dy/dx = dy/dθ • dθ/dx = (dy/dθ) / (dx/dθ)

dy/dx = (dr/dθ sin(θ) + r(θ) cos(θ)) / (dr/dθ cos(θ) - r(θ) sin(θ))

When θ = π/3, the slope is

dy/dx = (-4√3 sin(π/3) + 13 cos(π/3)) / (-4√3 cos(π/3) - 13 sin(π/3))

dy/dx = (-4√3 (√3/2) + 13 (1/2)) / (-4√3 (1/2) - 13 (√3/2))

dy/dx = - 1/(17√3)

So, the tangent line has slope -1/(17√3) and passes through (13/2, 13√3/2). Using the point-slope formula, its equation is

y - 13√3/2 = -1/(17√3) (x - 13/2)

y = -(x - 338)/(17√3)

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2 years ago