Hey there!
Let's create a systems of equations using x and y.
4x+3y=15
3x-2y=7
We need to solve this using elimination. First, we need to multiply the first equation by 2/3 so that we can cancel out the y's when combining our equations.
2 2/3x+2y=10
3x-2y=7
Now we combine the equations...
5 2/3x=17
x=3
Now we can plug our x into the first equation to find y.
12+3y=15
y=1
Our numbers are 3 and 1.
I hope this helps!
Answer: 11,830
Step-by-step explanation:
Answer:
no
yes
no
yes
Step-by-step explanation:
x input repeats - 3
x input doesn't repeat
x input repeats -4
x input doesn't repeat
Ax + By = C form of the given equation is –6x + y = –28.
Solution:
Given equation is y – 2 = 6(x – 5).
To write the equation in Ax + By = C format:
y – 2 = 6(x – 5)
y – 2 = 6x – 30
Add 2 on both sides of the equation.
y – 2 + 2 = 6x – 30 + 2
y = 6x – 28
Subtract 6x from both sides of the equation.
y – 6x = 6x – 28 – 6x
y – 6x = –28
Arrange the terms in the equation.
–6x + y = –28
This is in the form of Ax + By = C.
Here A = –6, B = 1 and C = –28.