<span>You are given a car moved at a constant velocity during the first hour. It stopped for 2 hours at a mall and then moved ahead again at a constant velocity for the next 3 hours. Then you are given the car that has finally returned to its starting point with a constant velocity in the next 2.5 hours. The graph that best represents the car's motion is First straight line joins ordered pairs 0, 0 and 1, 60, second straight line joins 1, 60 and 3, 60, third straight line joins 3, 60 and 6, 100 and fourth straight line joins 6, 100 and 8.5, 0.</span>
Answer:
1/40
219/250
69/16
Step-by-step explanation:
1.
0.025=(025)/(1000)=1/40
2.
0.876=876/1000=219/250
3.
4.3125=43125/10000=1725/400=69/16
See below for the terms, coefficients, and constants in the variable expressions
<h3>How to determine the terms, coefficients, and constants in the variable expressions?</h3>
To determine the terms, coefficients, and constants, we use the following instance:
ax + by + c
Where the variables are x and y
- Then the terms are ax, by and c
- The coefficients are a and b
- The constant is c
Using the above as guide, we have:
A) 2b + 2ac+5
- Terms: 2b, 2ac, 5
- Coefficient: 2, 2 and 5
- Constant 5
B) 34abx + 16y +1
- Terms: 34abx, 16y, 1
- Coefficient: 34ab, 16
- Constant: 1
C) st +4u + v
- Terms: st, 4u, v
- Coefficient: 4
D) 14xy + 6
- Terms: 14xy, 6
- Coefficient: 14, 6
- Constant 6
E) 14x + 12y
- Terms: 14x, 12y
- Coefficient: 14, 12
F) 3+ 6-7+a
- Terms: 3, 6, -7, a
- Coefficient: 1
- Constant: 3, 6, -7
Read more about terms, coefficients, and constants at:
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Answer:
the answer to that question is 12,600 rupees
