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Mashcka [7]
3 years ago
11

What are three names for 3.09

Mathematics
1 answer:
mixas84 [53]3 years ago
7 0

Answer:

1.Three and Nine Hundredths    2. 3 9/100      3. 390%

Step-by-step explanation:


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Help me with this please
victus00 [196]

Answer:

(4,2)

Step-by-step explanation:


3 0
3 years ago
How do i divide using polynomial long division
Umnica [9.8K]
1.divide the first term of the numerator by the first team of the denominator, and put that in the answer
2. Multiply the denominator by that answer, put that below the numerator
3.subtract to create a new polynomial
3 0
3 years ago
Barb signed up for an art club. She had to pay $50 to sign up for the club and
aleksandrvk [35]
5 weeks she went to the club.
8 0
3 years ago
A college is creating a new rectangular parking lot. the length is 0.17 mile longer than the width and the area of the parking l
Svetradugi [14.3K]
Let's call the width of the parking lot w.
The length of the parking lot if .17 more than the width so the length is w + .17

The parking lot is rectangular so its area is found by multiplying the length and the width. That is, the area is equal to what we obtain when we multiply w by w+.17. The area is: A = w(w+.17)= w^{2} +.17w

We are also told that the area is equal to .039 square miles so we set the expression we obtained for the area equal to .039 as follows.

w^{2} +.17w=.039

Since w represents the width of the rectangular lot, we can solve this equation for w to find the width. This is a quadratic equation (the highest exponent of the variable w is 2). We solve these by setting them equal to zero and then using the quadratic formula.

Setting our equation equal to zero (subtract .039 from both sides) gives us:
w^{2} +.17w-.039=0

The quadratic formula is as follows. Since the equation is in terms of w we write it as "w = ..." instead of the usual "x = ..."

w= \frac{-bplusminus \sqrt{ b^{2} -4ac} }{2a}

The part I write as "plusminus" is typically written with a + sign over a - sign. For right now let's leave it at that. Later in the problem we will see what it means and what to do with it.

To use the formula we have to identify a, b and c.

a is the coefficient of the squared term. That is, the number in front of w^{2} which here is 1.

b is the coefficient of the linear term. That is, the number in front of w which here is .17

c is the constant (the number by itself0 which is -.039

So we have:
a=1
b=.17
c=-.039

We plug these into the quadratic formula to obtain:
w= \frac{-.17plusminus \sqrt{ .17^{2} -(4)(1)(-.039)} }{(2)(1)}
w= \frac{-.17plusminus \sqrt{ .0289+.156} }{2}
w= \frac{-.17plusminus \sqrt{ .189} }{2}
w= \frac{-.17plusminus.43} {2}

Here is where the "pluminus" comes in. We continue to simplify the expression on the right but we split it in two. In one case we use "plus" and in the other "minus". That is, we add in one and subtract in the other. This gives us:
w= \frac{-.17+.43}{2}= \frac{.26}{2}=.13
and
w= \frac{-.17-.43}{2}= \frac{-.6}{2}=-.3

w is the width of the rectangular lot so it is a distance and cannot be measured using negative numbers. The width of the rectangular must be positive so we disregard the negative answer.

The width of the rectangle is .13 miles

Recall that the length of the rectangle is .17 more than the width. That is, the length is w+.17 and as we know the width to be .13 miles the length is .13 + .17 = .3 miles

The answer therefore is:
width = .13 miles
length = .3


4 0
3 years ago
Read 2 more answers
Mai has a dome paperweight that she can use as a magnifier. The paperweight is
Shkiper50 [21]

Answer:

6 x 6 x 3 cm

Step-by-step explanation:

The base of the box needs to fit the base of the hemisphere.

The maximum width and length of the hemisphere is the diameter of the base of the hemisphere (which is circular)

Diameter of a circle = 2r

As the radius = 3 cm,  the diameter = 2 x 3 = 6 cm

Therefore, the width and length of the box should both be 6cm

The height of the box needs to accommodate the height of the hemisphere.  The height of the hemisphere is the radius, so the height of the box should be 3 cm.

Therefore, the dimensions of the box should be 6 x 6 x 3 cm

6 0
3 years ago
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