Answer:
4/7
Step-by-step explanation:
2/7 x 3= 6/7. 6/7× 2/3=4/7
<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86
Answer:
.. .. ..
o = N - F :
.. ..
Under the N just leave empty
Step-by-step explanation:
The value of GK = 18.6, GM = 14.5 AND JZ = 19.9.
From the figure:
MZ is a perpendicular bisector of ∆GHJ.
GM = MJ
GM = 14.5
KZ is a perpendicular bisector of ∆GHJ.
GK = KH
GK = 18.6
Z is the circumcenter of ∆GHJ.
JZ = GZ
JZ = 19.9
Therefore the value of GK = 18.6, GM = 14.5 AND JZ = 19.9.
Learn more about the perpendicular bisector here:
brainly.com/question/24753075
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