The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.
Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11
Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
2 cases x 12 cans = 24 cans
24 cans x 54 oz per can = 1296 oz
1296 oz / 6 oz per serving = 216 guests served
Answer:
1
Explanation:
According to the Unit Circle, sin π\6 is ½, so we plug this into the cosine function to get this:
cos π\6 - π\6 → cos 0 >> 1
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** I do not have Unit Circle video uploaded yet, but if I need to, just notify me in the comments or on of course, You-Tube.
*** Plus, we need to make sure that the x-value falls in between 0 and π\2, which it did, so no need to worry.
15p^2q^2 because you multiply the coefficients and the vaiables. 3x5 is 15, pxp is p^2, and qxq is q^2
