Answer: -8, 1
Step-by-step explanation: on the y axis you go to where the side is opposite so in this case 8,1 in on the right do u go to the left of the y axis and the is a negative x axis and positive y so u get -8,1
![\dfrac\partial{\partial y}\left[e^{2y}-y\cos xy\right]=2e^{2y}-\cos xy+xy\sin xy](https://tex.z-dn.net/?f=%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5Be%5E%7B2y%7D-y%5Ccos%20xy%5Cright%5D%3D2e%5E%7B2y%7D-%5Ccos%20xy%2Bxy%5Csin%20xy)
![\dfrac\partial{\partial x}\left[2xe^{2y}-y\cos xy+2y\right]=2e^{2y}+y\sin xy](https://tex.z-dn.net/?f=%5Cdfrac%5Cpartial%7B%5Cpartial%20x%7D%5Cleft%5B2xe%5E%7B2y%7D-y%5Ccos%20xy%2B2y%5Cright%5D%3D2e%5E%7B2y%7D%2By%5Csin%20xy)
The partial derivatives are not equal, so the equation is not exact.
Answer:
Step-by-step explanation:
step 1
Find the length side PQ
we know that
The area of rectangle PQRS is given by
so
substitute the value of QR
solve for PQ
step 2
Find the length side AB
we know that
The perimeter of rectangle ABCD is given by
we have
substitute
solve for AB
Answer:
X=140
Step-by-step explanation:
<em>Firstly, any Quadrilateral has a total sum of its angle equal to 360 degrees</em>
<em>The attachment you are showing us shows that we already know two angles</em>
<em>(70)&(60) degrees. I am assuming the line DC is a tangent, so angle ADC must be 90 degrees since a full angle on a tangent is equal to 180 degrees and there is 90 from the other side (180-90=90). Now we know 3 angles and what you have to do is find X so that when you add them all up they make a sum of 360. </em>
<em />
X+70+60+90=360
X=360-70-60-90
X=140
