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OlgaM077 [116]
3 years ago
6

Which represents the solution set to the inequality 5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4)? ​

Mathematics
2 answers:
Tanya [424]3 years ago
8 0

Answer:

1. Simplify the inequality  5.1(3 + 2.2x) > -14.25 - 6(1.7x + 4):

15.3+11.22x>-14.25-10.2x-24 10;15.3+11.22x>-10.2x-38.75.  

2. Separate terms with x and without x in different sides:

11.22x+10.2x>-38.75-15.3.

3. Add similar terms:

21.42x>-54.05.  

4. Divide by 21.42:

x>-54.05/21.42

x>-2.5

Step-by-step explanation:

NISA [10]3 years ago
3 0

Answer: The answer is c on edge2020 good luck

Dont forget to click <u>THANKS</u>

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Answer:

Option C is correct

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Step-by-step explanation:

As per the statement:

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If there are 11 red marbles.

then;

Green marbles = Total marbles - red marbles.

Substitute the given values we have;

Green marbles = 44 - 11 = 33

We have to find  the ratio of green to red marbles.

\frac{\text{Green marbles}}{\text{Red marbles}} = \frac{33}{11} = \frac{3}{1} = 3 : 1

Therefore,  the ratio of green to red marbles is, 3 : 1

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Solve the following ODE's: c) y* - 9y' + 18y = t^2
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Answer:

y = C_1e^{3t}+C_2e^{6t} + \dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

m² - 9 m + 18 = 0

m² - 3 m - 6 m+ 18 = 0

(m-3)(m-6) = 0

m = 3,6

C.F. = C_1e^{3t}+C_2e^{6t}

now calculating P.I.

P.I. = \frac{t^2}{D^2 - 9D +18}

P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

hence the complete solution

y = C.F. + P.I.

y = C_1e^{3t}+C_2e^{6t} + \dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

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3 years ago
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