In 1993, Moose Population: 3280
In 1999, population became: 4960
P (Population) , t (years)
t = 6 —> 4960 - 3280 = 1680
Average Change —> 1680/6 = 280 moose/year
• In terms of 1990:
t = 3 —> 3280-3 (280)
P(1990) = 2440
P(t) = 2440 + 280t
• In 2003; t = 13
P(13) = 2440 + 280 (13)
P(13) = 2440 + 3640
P(13) = 6080
• Moose population in 2003
= 6080
Answer:
271
Step-by-step explanation:
Answer:
350
Step-by-step explanation:
Gimmie brainliest plzzz <3
Reflected across the x-axis, the function becomes
... g(x) = -f(x) = -20 +4x
This models the situation in which the car is driving in reverse, is accelerating (velocity is becoming less negative), and comes to a stop in 5 seconds.
Of the choices offered, the best seems to be ...
... b. the car immediately begins to accelerate at the same rate it had previously decelerated.
