Answer:
The electrical force between two balloons is 67.5N.
Explanation:
There are two charged balloons, let's say a and b.
The charge on the balloon a =
C
The charge on the balloon b =
C
Both balloons are 1 cm apart; it means that the distance<em> r</em> between the balloon a and the balloon b is 0.01 m (since 1 cm = 0.01 m).
We need to find the electrical force between them. By using the Coulomb's law, the magnitude of the electrical force between both the balloon is given as follows:
--- (A)
Where,
k = Coulomb's constant =
= ![9 * 10^9 \frac{Nm^2}{C^2}](https://tex.z-dn.net/?f=9%20%2A%2010%5E9%20%5Cfrac%7BNm%5E2%7D%7BC%5E2%7D)
Plug all the values in the equation (A):
![F = \frac{(9*10^9)(3.0*10^{-6})(2.5*10^{-7})}{(0.01)^2} \\F = 67.5 N](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B%289%2A10%5E9%29%283.0%2A10%5E%7B-6%7D%29%282.5%2A10%5E%7B-7%7D%29%7D%7B%280.01%29%5E2%7D%20%5C%5CF%20%3D%2067.5%20N)
Hence, the electrical force between two balloons is 67.5N (three significant figures).
Explanation:
F = 20N m= m1 a=10m/s²
m=m2 a=5m/s²
F = ma
<u>for the first one</u><u>:</u><u> </u>
f=m1 × a
20 = m1 ×10
20=10m1
m1=20/10
m1=2
<u>for</u><u> </u><u>the</u><u> </u><u>second</u><u> </u><u>one</u><u> </u><u>:</u>
f=m2×a
20=m2×5
m2= 20/5
m2= 4
since F=ma
F=(m1+m2) ×a
F =(4+2)×a
F =6×a
F=20(from the question above )
20=6×a
a=20/6
a=3.33
Do you have a picture then I could determine 1 millimeter