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3 years ago

5

The table below shows the average wind speeds of four hurricanes in Florida

2 answers:

lara31 [8.8K]3 years ago

7 0

Hurricane A. This is because the wind speed of this hurricane is greater than the other hurricanes. The more wind there is in a hurricane the more land and home destruction it’s likely to cause. Hope this helps. :)

Lyrx [107]3 years ago

7 0

Answer:

A is right

Explanation:

I took the test

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Which tools would sara us to find an irregularly shaped objects mass and volume A. a meter stick , a ruler , and water

tester [92]

I think it's D. Usually, to find the volume of an irregularly shaped object, you put it in water with a labeled beaker to measure how much the water rises. The balance would be used to measure the mass in grams.

4 0

3 years ago

A person exerts a tangential force of 37.7 N on the rim of a disk-shaped merry-go-round of radius 2.75 m and mass 144 kg. If the

Shkiper50 [21]

Answer:

ω = 0.467 rad/s

Explanation:

given,

tangential force exerted by the person = 37.7 N

radius of merry-go-round = 2.75 m

mass of merry-go-round = 144 Kg

angle = 33.2°

moment of inertia

$I = \dfrac{1}{2} m R^2$

$I = \dfrac{1}{2}\times 144 \times 2.75^2$

I = 544.5 kg.m²

torque = force x radius

τ = 37.7 x 2.75

τ = 103.675 N.m

angular acceleration

$\alpha= \dfrac{\tau}{I}$

$\alpha= \dfrac{103.675}{544.5}$

α = 0.190 rad/s²

now ,

distance = $33.2\times \dfrca{2\pi}{360}$

d = 0.579 rad

we know,

using equation of rotational motion

$d = \omega t + \dfrac{1}{2}\alpha t^2$

$0.579 = \dfrac{1}{2}\times 0.190\times t^2$

t = 2.46 s

angular speed

ω = α x t

ω = 0.19 x 2.46

ω = 0.467 rad/s

7 0

3 years ago

Solve for x. 4(x+1)≤4x+3

alexdok [17]

4x + 4 < 4x + 3 (expand it)
4 < 3 (cancel 4x on both sides)
Since 4 < 3 is not true there is no solution.

Answer: NO SOLUTION.

3 0

3 years ago

Read 2 more answers

How many meters are in 32 kilometers

lukranit [14]

Answer:

32,000 m

Explanation:

Conversion

1km ===> 1000m

32km===>x

x = (32 × 1000) ÷ 1

5 0

3 years ago

In a ballistics test, a 52g bullet hits a sand bag and stops after moving 1.34 m. If the initial bullat

olya-2409 [2.1K]

Answer:

Friction force on the bullet is 58.7 N opposite to its velocity

Explanation:

As we know that initial speed of the bullet is 55 m/s

after travelling into the sand bag by distance d = 1.34 m it comes to rest

so final speed

$v_f = 0$

now we can use kinematics top find the acceleration of the bullet

$v_f^2 - v_i^2 = 2 a d$

so we have

$0 - 55^2 = 2(a)(1.34)$

$a = -1128.7 m/s^2$

now by Newton's II law we know that

$F = ma$

so we have

$F = (0.052)(-1128.7)$

$F = -58.7 N$

8 0

3 years ago