Answer is: there is 3,36 micrograms of iron in <span>sample of Greg's blood.
</span>m(Fe) = 42 mcg(micrograms).
V(Fe) = 1 dL = 1 dL · 100 mL/1dL.
V(Fe) = 100 mL.
Make proportion: m(Fe) : 8 mL = 42 mcg : 100 mL.
100 mL · m(Fe) = 8 mL · 42 mcg.
m(Fe) = 336 mL·mcg ÷ 100 mL.
m(Fe) = 3,36 mcg.
Answer:
Cu₃(PO₄)₂(s), RbNO₃(aq)
Explanation:
This reaction looks like a possible <em>double replacement reaction</em>, in which the metal ions have exchanged partners.
3Cu(NO₃)₂(aq) + 2Rb₃PO₄(aq) ⟶ Cu₃(PO₄)₂ + 6RbNO₃
You must recall the pertinent <em>solubility rules</em>:
1. Salts of Group 1 elements (e.g., Rb⁺) are soluble.
2. Salts containing nitrate ions (NO₃⁻) are soluble.
3. Most salts containing phosphate ions (PO₄³⁻) are insoluble
According to Rules 1 and 1, RbNO₃ is soluble.
According to Rule 3, Cu₃(PO₄)₂ is insoluble.
∴ 3Cu(NO₃)₂(aq) + 2Rb₃PO₄(aq) ⟶ Cu₃(PO₄)₂(s) + 6RbNO₃(aq)
I believe the four series you are looking for are straight-chain alkanes, alkenes, and alkynes, and cycloalkanes. These all have the same repeating of CH2 as the base group, while alkenes have a double bond somewhere in the molecule, and alkynes a triple somewhere.
Answer: what is this sorry