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TiliK225 [7]
3 years ago
11

Predict the product(s) of the following reaction. (Separate substances in a list with a comma. Include states-of-matter under th

e given conditions in your answer.) Cu(NO3)2 + Rb3PO4 ------>(H2O above the arrow)
Chemistry
1 answer:
kiruha [24]3 years ago
6 0

Answer:

Cu₃(PO₄)₂(s), RbNO₃(aq)

Explanation:

This reaction looks like a possible <em>double replacement reaction</em>, in which the metal ions have exchanged partners.

3Cu(NO₃)₂(aq) + 2Rb₃PO₄(aq) ⟶ Cu₃(PO₄)₂ + 6RbNO₃

You must recall the pertinent <em>solubility rules</em>:

1. Salts of Group 1 elements (e.g., Rb⁺) are soluble.

2. Salts containing nitrate ions (NO₃⁻) are soluble.

3. Most salts containing phosphate ions (PO₄³⁻) are insoluble

According to Rules 1 and 1, RbNO₃ is soluble.

According to Rule 3, Cu₃(PO₄)₂ is insoluble.

∴ 3Cu(NO₃)₂(aq) + 2Rb₃PO₄(aq) ⟶ Cu₃(PO₄)₂(s) + 6RbNO₃(aq)

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Which element could provide one atom to make an ionic bond with fluorine
Drupady [299]
Lithium i believe is the answer
8 0
3 years ago
One mole of aluminum atoms has a mass of 27 grams. How many grams are in 9.0 moles of aluminum?
gizmo_the_mogwai [7]
27*9=243 if one mole is equal to 27 grams times that by 9
6 0
2 years ago
What can occur in physical change ?
Alexandra [31]

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Hope this helped

5 0
3 years ago
If the half-life of a radioisotope is 10,000 years, the amount remaining after 20,000 years is
Cloud [144]

Answer:

Considering the half-life of 10,000 years, after 20,000 years we will have a fourth of the remaining amount.

Explanation:

The half-time is the time a radioisotope takes to decay and lose half of its mass. Therefore, we can make the following scheme to know the amount remaining after a period of time:

Time_________________ Amount

t=0_____________________x

t=10,000 years____________x/2

t=20,000 years___________x/4

During the first 10,000 years the radioisotope lost half of its mass. After 10,000 years more (which means 2 half-lives), the remaining amount also lost half of its mass. Therefore, after 20,000 years, the we will have a fourth of the initial amount.

6 0
3 years ago
Wht are the trends for electronegativity and ionzation energy similar​
FinnZ [79.3K]

Answer:

Along period electronegativity and ionization energy increases.

Along group electronegativity and ionization energy decreases.

Explanation:

Along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. Thus the attraction of the atoms for valance electrons increases. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required, and electronegativity also increases.

Along group:

As we move from top to bottom in periodic table the atomic sizes increases.The electrons are added in next energy level in every next element. Thus the valance electrons farther away from the nucleus and hold of nucleus becomes weaker,  because of weak nuclear attraction atomic radii increases and electronegativity and ionization energy decreases.

3 0
2 years ago
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