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NeX [460]
4 years ago
6

The reaction a(g) + 2b(g) c(g) was allowed to come to equilibrium. the initial amounts of reactants placed into a 5.00 l vessel

were 1.0 mol a and 1.8 mol
b. after the reaction reached equilibrium, 1.0 mol of b was found. calculate kc for this reaction.
Chemistry
1 answer:
earnstyle [38]4 years ago
5 0
Answer is: Kc for reaction is 16.66.
Chemical reaction: A + 2B ⇄ C.
c₀(A) = 1 mol ÷ 5 L; initial concentration of A.
c₀(A) = 0,2 mol/L.
c₀(B) = 1,8 mol ÷ 5 L; initial concentration of B.
c₀(B) = 0,36 mol/L.
c(B) = 1 mol ÷ 5 L.
c(B) = 0,2 mol/L; equilibrium concentration of B.
From chemical reaction: n(A) : n(B) = 1 : 2.
n(A) = 0,8 mol ÷ 2 = 0,4 mol.
c(A) = (1 mol - 0,4 mol) ÷ 5 L.
c(A) = 0,12 mol/L; equilibrium concentration of A.
n(C) : n(B) = 1 : 2.
n(C) = 0,4 mol.
c(C) = 0,4 mol ÷ 5 L.
c(C) = 0,08 mol/L; equilibrium concentration of C.
Kc = 0,08 mol/L ÷ ((0,2 mol/L)² ·0,12 mol/L).
Kc = 16,66.

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If the rate of decomposition of ammonia, NH3, at 1150 K is 2.10 x 10-6 mol/L/s, what is the
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Answer:

3.15 × 10⁻⁶ mol H₂/L.s

1.05 × 10⁻⁶ mol N₂/L.s

Explanation:

Step 1: Write the balanced equation

2 NH₃ ⇒ 3 H₂ + N₂

Step 2: Calculate the rate of production of H₂

The molar ratio of NH₃ to H₂ is 2:3. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of H₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 3 mol H₂/2 mol NH₃ = 3.15 × 10⁻⁶ mol H₂/L.s

Step 3: Calculate the rate of production of N₂

The molar ratio of NH₃ to N₂ is 2:1. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of N₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 1 mol N₂/2 mol NH₃ = 1.05 × 10⁻⁶ mol N₂/L.s

3 0
3 years ago
How do I know the point which a solid will turn to a liquid?
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There is a special temperature for every substance called the melting point. When a solid reaches the temperature of its melting point, it can become a liquid.  

4 0
3 years ago
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2. Suppose that 21.37 mL of NaOH is needed to titrate 10.00 mL of 0.1450 M H2SO4 solution.
AysviL [449]

Answer:

0.1357 M

Explanation:

(a) The balanced reaction is shown below as:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

(b) Moles of H_2SO_4 can be calculated as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For H_2SO_4 :

Molarity = 0.1450 M

Volume = 10.00 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 10×10⁻³ L

Thus, moles of H_2SO_4 :

Moles=0.1450 \times {10\times 10^{-3}}\ moles

Moles of H_2SO_4  = 0.00145 moles

From the reaction,

1 mole of H_2SO_4 react with 2 moles of NaOH

0.00145 mole of H_2SO_4 react with 2*0.00145 mole of NaOH

Moles of NaOH = 0.0029 moles

Volume = 21.37 mL = 21.37×10⁻³ L

Molarity = Moles / Volume = 0.0029 /  21.37×10⁻³  M = 0.1357 M

7 0
3 years ago
Give the name, atomic symbol, and group number of the element with each Z value, and classify it as a metal, metalloid, or nonme
Viktor [21]

Atomic number = 42

Name = Molybdenum

Atomic symbol  = Mo

Group number = VI(B)6

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How to find all valves of Z=42?

Here, we are going to find out the name, symbol and group numbers element with the following Z value and their classification as a metal, metalloid, or nonmetal.

The atomic number of the element is 42

Therefore, the name of the element is Molybdenum

The atomic symbol of the element is Mo

The group number of  is VI(B)6

Mo is a metal

Hence, the element is  Molybdenum

Learn more about atomic symbol here :

brainly.com/question/930789

#SPJ4

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