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Luden [163]
3 years ago
14

Help me please ???????

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
5 0

Answer:

it is the  last one give me 5 stars  thanks

Step-by-step explanation:

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How would I figure out a linear equation with two plot points with fractions? (1/3(6),3) and (1/2(19),-2) are my two plot points
murzikaleks [220]

Answer: m=\frac{-30}{79},\ y=5.40

Step-by-step explanation:

Given

Points are \left(6\frac{1}{3},3\right),\ \left(19\frac{1}{2},-2\right)

Convert mixed numeral to fraction

\left(6\frac{1}{3},3\right)\Rightarrow \left(\dfrac{19}{3},3\right)\\\\\left(19\frac{1}{2},-2\right)\Rightarrow \left(\dfrac{39}{2},-2\right)

Slope of the line is

\Rightarrow m=\dfrac{3-(-2)}{\dfrac{19}{3}-\dfrac{39}{2}}\\\\\Rightarrow m=\dfrac{5}{\dfrac{38-117}{6}}\\\\\Rightarrow m=\dfrac{-30}{79}

Equation of line

\Rightarrow \dfrac{y-3}{x-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\text{for y-intercept, put x=0}\\\\\Rightarrow \dfrac{y-3}{0-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\Rightarrow y-3=\dfrac{190}{79}\\\\\Rightarrow y=3+2.40\\\Rightarrow y=5.40

3 0
3 years ago
F(x)=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2-4%7D" id="TexFormula1" title="\sqrt{x^2-4}" alt="\sqrt{x^2-4}" align="abs
hammer [34]

Solve for <em>x</em> when √(<em>x</em> ² - 4) = 1 :

√(<em>x</em> ² - 4) = 1

<em>x</em> ² - 4 = 1

<em>x</em> ² = 5

<em>x</em> = ±√5

We're looking at <em>x </em>≤ 0, so we take the negative square root, <em>x</em> = -√5.

This means <em>f</em> (-√5) = 1, or in terms of the inverse of <em>f</em>, we have <em>f</em> ⁻¹(1) = -√5.

Now apply the inverse function theorem:

If <em>f(a)</em> = <em>b</em>, then  (<em>f</em> ⁻¹)'(<em>b</em>) = 1 / <em>f '(a)</em>.

We have

<em>f(x)</em> = √(<em>x</em> ² - 4)   →   <em>f '(x)</em> = <em>x</em> / √(<em>x</em> ² - 4)

So if <em>a</em> = -√5 and <em>b</em> = 1, we get

(<em>f</em> ⁻¹)'(1) = 1 / <em>f '</em> (-√5)

(<em>f</em> ⁻¹)'(1) = √((-√5)² - 4) / (-√5) = -1/√5

The sign must be negative; see the attached plot, and take note of the negatively-sloped tangent line to the inverse of <em>f</em> at <em>x</em> = 1.

3 0
3 years ago
Which equation has no solution?
konstantin123 [22]

Answer:

B) 4x-5-3x=x+5 has no solution.

Step-by-step explanation:

A) 4x+4=4-4x

4x-(-4x)+4=4

4x+4x+4=4

8x+4=4

8x=4-4

8x=0

x=0/8

x=0

------------------

B) 4x-5-3x=x+5

4x-3x-5=x+5

x-5=x+5

x-x-5=5

-5=5

no solution.

------------------------

C) 4x+15-9x=5x+15

4x-9x+15=5x+15

-5x+15=5x+15

-5x-5x+15=15

-10x+15=15

-10x=15-15

-10x=0

x=0/-10

x=0

------------------------

D) 4x+2-x=4+3x-2

3x+2=3x+4-2

3x+2=3x+2

infinitely many solutions.

8 0
2 years ago
Which of the following is the quotient of rational expressions shown below?
emmasim [6.3K]

Answer: 6x - 3 over x^3

Step-by-step explanation:

7 0
3 years ago
Find (if possible) the complement and the supplement of each angle. (if not possible, enter impossible.) (a) π 10 complement rad
blagie [28]

In this question, we have to find the complement and supplement of the given angles .

Complementary angles are those angles whose sum is 90 degree and supplementary angles are those angles whose sum is 180 degree.

So to find the complement and supplement angles, we need to subtract the given angles from pi/2 and pi respectively .

a.

\frac{ \pi}{10}&#10;\\&#10;complement  \ angle = \frac{ \pi}{2} - \frac{ \pi}{10}     \\                             = \frac{4 \pi}{10} = \frac{ 2 \pi}{5}&#10;\\&#10;Supplement  \ angle = \pi - \frac{ \pi}{10} = \frac{9 \pi}{10}

b.

\frac{9 \pi}{10}&#10;\\&#10;Complement \ angle = \frac{ \pi}{2} - \frac{9 \pi}{10} = \frac{-4 \pi}{10} = -\frac{2 \pi}{5}&#10;\\&#10;Supplement \ angle = \pi - \frac{9 \pi}{10} = \frac{ \pi}{10}

4 0
3 years ago
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